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can someone explain how to get the solution to IF7 problem d?
 10 months ago
 10 months ago
can someone explain how to get the solution to IF7 problem d?
 10 months ago
 10 months ago

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OBMDBest ResponseYou've already chosen the best response.0
Here is how I did the problem. First change \[Q=(at)(1+bt ^{2})^{3}\] Then use the product rule to get \[a(1+bt ^{2})^{3}+at(3)(1+bt ^{2})^{4}(2bt)\] I then used the fact that \[a(1+bt ^{2})^{3}=\frac{ a }{(1+bt ^{2})^{3}}=\frac{a(1+bt ^{2})}{(1+bt ^{2})^{3}}=\frac{ a+abt ^{2} }{ (1+bt ^{2})^{3} }\] to get \[\frac{ a+abt ^{2} }{ (1+bt ^{2})^{4} }+\frac{ 6abt ^{2} }{ (1+bt ^{2})^{4} }\] which simplifies to \[\frac{ a5abt ^{2} }{ (1+bt ^{2})^{4} }=\frac{ a(15bt ^{2} }{ (1+bt ^{2})^{4} }\]
 10 months ago

OBMDBest ResponseYou've already chosen the best response.0
Two corrections on the third line of equations (darn cut and paste). It should look like this \[a(1+bt ^{2})^{3}=\frac{ a }{ (1+bt ^{2})^{3} }=\frac{ a(1+bt ^{2}) }{ (1+bt ^{2})^{4} }=\frac{ a+abt ^{2} }{ (1+bt ^{2})^{4} }\]
 10 months ago
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