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Clarkmonsterman
 one year ago
can someone explain how to get the solution to IF7 problem d?
Clarkmonsterman
 one year ago
can someone explain how to get the solution to IF7 problem d?

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OBMD
 one year ago
Best ResponseYou've already chosen the best response.0Here is how I did the problem. First change \[Q=(at)(1+bt ^{2})^{3}\] Then use the product rule to get \[a(1+bt ^{2})^{3}+at(3)(1+bt ^{2})^{4}(2bt)\] I then used the fact that \[a(1+bt ^{2})^{3}=\frac{ a }{(1+bt ^{2})^{3}}=\frac{a(1+bt ^{2})}{(1+bt ^{2})^{3}}=\frac{ a+abt ^{2} }{ (1+bt ^{2})^{3} }\] to get \[\frac{ a+abt ^{2} }{ (1+bt ^{2})^{4} }+\frac{ 6abt ^{2} }{ (1+bt ^{2})^{4} }\] which simplifies to \[\frac{ a5abt ^{2} }{ (1+bt ^{2})^{4} }=\frac{ a(15bt ^{2} }{ (1+bt ^{2})^{4} }\]

OBMD
 one year ago
Best ResponseYou've already chosen the best response.0Two corrections on the third line of equations (darn cut and paste). It should look like this \[a(1+bt ^{2})^{3}=\frac{ a }{ (1+bt ^{2})^{3} }=\frac{ a(1+bt ^{2}) }{ (1+bt ^{2})^{4} }=\frac{ a+abt ^{2} }{ (1+bt ^{2})^{4} }\]
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