anonymous
  • anonymous
Find the sum of the geometric series.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
The sum of a geometric series: x^0 + x^1 + x^2 + . . . + x^(n-2) + x^(n-1) + x^n is [x^(n+1) - 1] / (x - 1) Here, you have: 81[1 + (1/3)^1 + (1/3)^2 + . . . + (1/3)^6] (81)[(1/3)^7 - 1] / [(1/3) - 1]
anonymous
  • anonymous
All good now, @ladyrosebud ?

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anonymous
  • anonymous
Well I did that and keep getting the wrong answer. I get 121.4. Idk what it is
Zarkon
  • Zarkon
what are the directions on how the answer should be formatted?
anonymous
  • anonymous
I also get: 121.44444444444444444444444444444 Perhaps you are needing to put the answer in a different format? Maybe fractions?
anonymous
  • anonymous
The answers are just regular numbers and fractions. Here's what they have a. 1093/9 b.91 c.101 d.15/7
anonymous
  • anonymous
Oh it's A isn't it?
Zarkon
  • Zarkon
yes
anonymous
  • anonymous
first one
anonymous
  • anonymous
oh okay thanks!
anonymous
  • anonymous
uw!
anonymous
  • anonymous
Good luck to you in all of your studies and thx for the recognition! @ladyrosebud
anonymous
  • anonymous
Thank you:) and it really helped! I was just overlooking the answer, lol
anonymous
  • anonymous
You did well! np!

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