anonymous
  • anonymous
1. In the diagram below, line segment AT is a diameter of the circle with center O. What is the area of the shaded part of the circle? Show your work or provide an explanation for your answer.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
can someone help me?
Notamathgenius
  • Notamathgenius
I'm not really good with this stuff sorry D:

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anonymous
  • anonymous
its okay..
anonymous
  • anonymous
@touseii45
anonymous
  • anonymous
okay well you want to find the area of the circle first
anonymous
  • anonymous
so do you know your formula?
anonymous
  • anonymous
the area is 201.1
anonymous
  • anonymous
OK, first find the area of the circle, which is \[\pi \times r ^{2}\] and r is half of the diameter Next find the area of the triangle. To do that, calculate the base and the height, using the fact that u know the hypothenuse and the angle 30. Than use the formula : area of a triangle=0.5xheightxbase
anonymous
  • anonymous
now youve lost me :(
anonymous
  • anonymous
what he means is 3.14 (which is pi) times r squared (or half of the diameter times itself)
anonymous
  • anonymous
i know the area of the circle
anonymous
  • anonymous
if your diameter is 16 divide that by 2
anonymous
  • anonymous
what is it?
anonymous
  • anonymous
the area is 201.1
anonymous
  • anonymous
correct now do you have the area of the triangle?
anonymous
  • anonymous
no, i cant figure out how..
anonymous
  • anonymous
ok, do u know that sinx=opposite/hypothenuse ?
anonymous
  • anonymous
and that cosx=adjacent/hypothenuse? u can use these two facts to find the base and the height of the triangle
anonymous
  • anonymous
im sorry thanks for your help, but im more confused than before i cane here
anonymous
  • anonymous
im confused too
anonymous
  • anonymous
did u learn about sine and cosine? If u haven't, than I don't see how u could solve this question
anonymous
  • anonymous
yes.
anonymous
  • anonymous
alittle
anonymous
  • anonymous
so what exactly do i do to find the area of the triangle
anonymous
  • anonymous
OK, so \[\sin (of an \angle)=\frac{side opposite \to \angle }{ hypothenuse (the longest side of the \triangle }\]
anonymous
  • anonymous
and \[\cos x=\frac{ adjacent }{ hypothenuse }\]
anonymous
  • anonymous
but which fdo i do?
anonymous
  • anonymous
you throwing formulas at me is just confusing me
anonymous
  • anonymous
therefore, to find the base of the triangle, we calculate: \[\sin(30)=\frac{ base }{ 16 }\] and to find the height of the triangle, we calculate: \[\cos (30)=\frac{ height }{ 16 }\]
anonymous
  • anonymous
I'm sorry, I'm not trying to confuse, I'm just working through the problem with u
anonymous
  • anonymous
oohhhh okay!!1
anonymous
  • anonymous
we got it?
anonymous
  • anonymous
:D
anonymous
  • anonymous
but how do i solve them?
anonymous
  • anonymous
well, \[the base=16\sin 30\] \[the height=16\cos 30\]
anonymous
  • anonymous
so? 8 and 13.86
anonymous
  • anonymous
ok, now we plug that into the triangle fornmula (which is half times base times height) And then we subtract the area of the triangle from that of the circle
anonymous
  • anonymous
55.44 and 201.1-5544=145.66 os that right?
anonymous
  • anonymous
55.44***
anonymous
  • anonymous
:D well done! that's what i got, anyways
anonymous
  • anonymous
so final answer=145.636304
anonymous
  • anonymous
:)

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