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anonymous
 3 years ago
What are the points of discontinuity? Are they all removable?
y = (x3)/x^2  12x + 27
anonymous
 3 years ago
What are the points of discontinuity? Are they all removable? y = (x3)/x^2  12x + 27

This Question is Closed

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1When is the bottom 0?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1For what values of x make the bottom 0?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1So you should be able to solve an equation in this form ax^2+bx+c=0 by now. I'm guessing this since this is a type of problem that occurs after learning that.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Do you know how to factor?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Or even use the quadratic formula to solve a quadratic equation?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1You can even do completing the square.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Do you have 12x or +12x?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Hmmm...So the problem above is written/typed wrongly I assume. Okay You should know how to factor the polynomial x^2+12x+27

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Find two factors of c that add up to be b (you can do this when the coefficient of x^2 is 1 which in this problem it is)

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1In other words find two factors of 27 that add up to be 12.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its like this dw:1370027288868:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1I'm really confused what problem we are doing because twice now you have written +12x

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1You have also said twice that we have 12x

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Anyways, we take the bottom polynomial whatever it may be and set that equal to zero and solve for x. I will let you do it since I don't know what problem we are doing anymore.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is the problem were doing

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Set bottom polynomial equal to zero. \[x^212x+27=0\] You will notice this is in the form \[ax^2+bx+c=0\] You have learned if you cannot factor this easily you could also use completing the square or quadratic formula. The easy way to solve this quadratic is by factoring in my opinion. Since the coefficient of x squared is 1, all we have to really do is find two factors of c that add up to be b; called them m and n. So The factored form would be (xm)(xn)=0 Then you set both factors equal to 0 like so xm=0 or xn=0 Solve both for x like so x=m or x=n

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so which numbers do we use for xm and xn?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Have you found factors of 27 that have product 27 and sum 12?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Those are your m and n.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Recall this part that I said: Since the coefficient of x squared is 1, all we have to really do is find two factors of c that add up to be b; called them m and n.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1370027980807:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1See how I factored 27?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.11(27)=27 3(9)=27 1(27)=27 3(9)=27

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes I see on my answes I have x= 9, x =3 is that right?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Do any of those factors above that multiplied to be 27 also add up to be 12?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are these numbers removable?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1(x3)(x9)=0 Set both equal to 0.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1I put (xm)(xn)=0 where I meant (x+m)(x+n)=0. So you would have x+m=0 or x+n=0 Which means you would have x=m or x=n. But anyways we have (x3)(x9)=0 And you are to set both factors equal to 0 and solve for x for both equations

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1x3=0 or x9=0 I leaving solving these linear equations to you.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do we also use 1 or no?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Where does that come from?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Have you solve x3=0 or x9=0 yet?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1x3=0 You can't solve this for x? You don't know how to get x by itself?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1To undo subtraction by three you add three.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Try adding three to both sides and tell me what the result is.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1x3=0 add 3 to both sides +3 +3  what is the result?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1what is 3+3? what is 0+3?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1yes so x3+3=0+3 gives us x+0=3 Or just x=3

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1What are you going to add to both sides?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Discontinuous at x=3 or x=9

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Now go back to the problem where you had everything factored.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{x3}{(x3)(x9)}\]

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1This was the problem where everything is factored, correct?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Does anything cancel? If so that is where you have your removable discontinuity.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1x3 is just a number so is x9 If we had 5/(5*9) you would say the 5's cancel right? Like this 1/9 Does anything cancel? Is there a factor on top that you see on bottom?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{(x3)}{(x3)(x9)}\] If you want you can put parenthesis around the x3 on top, Do you see any factors that match on top and bottom?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1This is just like matching socks.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1I have to go to the grocery store. Good luck.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks for all ur help
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