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chikaa

  • one year ago

integral of cos(3x-5)^2

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  1. amrmagdy
    • one year ago
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    use double angles rules

  2. amrmagdy
    • one year ago
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    cos2x=2cosx-1 .. did you get it ?

  3. chikaa
    • one year ago
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    and what about the cos^2

  4. amrmagdy
    • one year ago
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    sry cos2x=2cosx^2-1

  5. myininaya
    • one year ago
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    Recall the double angle identity for cosine. \[\cos(2 \alpha )=\cos^2(\alpha)-\sin^2(\alpha)=\cos^2(\alpha)-(1-\cos^2(\alpha))\] \[\cos(2 \alpha)=\cos^2(\alpha)-1+\cos^2(\alpha)\] \[\cos(2 \alpha)=2 \cos^2(\alpha)-1\] Solve this equation for cos^2(alpha): \[\cos^2(\alpha)=\frac{1}{2}(1+\cos(2 \alpha))\]

  6. chikaa
    • one year ago
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    Thank you Amrmagdy and Myininaya :D

  7. amrmagdy
    • one year ago
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    urw

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