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anonymous
 3 years ago
how to find the general solution:
dP/dt=kP cos(rtv)^2
k, r and v are positive constants
anonymous
 3 years ago
how to find the general solution: dP/dt=kP cos(rtv)^2 k, r and v are positive constants

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myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Separation of variables is needed.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Put the problem in this form and the integrate both sides. \[g(p) dp=f(t) dt \]

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1You can picture those k, r , and v's being like 1,2, and 3's. They are just constants. You need your P's together and your t's together. I don't care and you shouldn't care where this puts the constants.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1You can actually leave k on the side it is on or divide both sides by k. It doesn't matter.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is what I got: \[P=\exp(\frac{ k }{ 2r }\sin(2rt2v)+\frac{ kt }{ 2 })\] However, this is what I should be getting according to the answer n my tutorial: \[P=\exp((\frac{ k }{ 2r }\sin(2rt2v)+\frac{ kt }{ 2 }\]\[+\frac{ k }{ 2r }\sin(2v))\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't get where the last bit came from

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1So did you set if up like I told you to?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{p} dp=k \cos^2(rtv) dt\]

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1\[\lnp=k \int\limits_{}^{} \frac{1}{2}(\cos(2[rtv]+1) dt\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah that's what I did

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i'm just not getting the last bit k/2r sin(2v)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0help needed urgently!!!

KenLJW
 3 years ago
Best ResponseYou've already chosen the best response.0dP/dt=kP cos(rtv)^2 dP/P=kcos(rtv)^2dt ln(P)=(k/3r)cos(rtv)^3 check with taking the Derivative with chain rule P=C1EXP[(k/3r)cos(rtv)^3
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