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chikaa
Group Title
how to find the general solution:
dP/dt=kP cos(rtv)^2
k, r and v are positive constants
 one year ago
 one year ago
chikaa Group Title
how to find the general solution: dP/dt=kP cos(rtv)^2 k, r and v are positive constants
 one year ago
 one year ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.1
Separation of variables is needed.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Put the problem in this form and the integrate both sides. \[g(p) dp=f(t) dt \]
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You can picture those k, r , and v's being like 1,2, and 3's. They are just constants. You need your P's together and your t's together. I don't care and you shouldn't care where this puts the constants.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You can actually leave k on the side it is on or divide both sides by k. It doesn't matter.
 one year ago

chikaa Group TitleBest ResponseYou've already chosen the best response.0
this is what I got: \[P=\exp(\frac{ k }{ 2r }\sin(2rt2v)+\frac{ kt }{ 2 })\] However, this is what I should be getting according to the answer n my tutorial: \[P=\exp((\frac{ k }{ 2r }\sin(2rt2v)+\frac{ kt }{ 2 }\]\[+\frac{ k }{ 2r }\sin(2v))\]
 one year ago

chikaa Group TitleBest ResponseYou've already chosen the best response.0
I don't get where the last bit came from
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
So did you set if up like I told you to?
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
And then integrate?
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{1}{p} dp=k \cos^2(rtv) dt\]
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\lnp=k \int\limits_{}^{} \frac{1}{2}(\cos(2[rtv]+1) dt\]
 one year ago

chikaa Group TitleBest ResponseYou've already chosen the best response.0
yeah that's what I did
 one year ago

chikaa Group TitleBest ResponseYou've already chosen the best response.0
i'm just not getting the last bit k/2r sin(2v)
 one year ago

chikaa Group TitleBest ResponseYou've already chosen the best response.0
help needed urgently!!!
 one year ago

KenLJW Group TitleBest ResponseYou've already chosen the best response.0
dP/dt=kP cos(rtv)^2 dP/P=kcos(rtv)^2dt ln(P)=(k/3r)cos(rtv)^3 check with taking the Derivative with chain rule P=C1EXP[(k/3r)cos(rtv)^3
 one year ago
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