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chikaa
 one year ago
how to find the general solution:
dP/dt=kP cos(rtv)^2
k, r and v are positive constants
chikaa
 one year ago
how to find the general solution: dP/dt=kP cos(rtv)^2 k, r and v are positive constants

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myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Separation of variables is needed.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Put the problem in this form and the integrate both sides. \[g(p) dp=f(t) dt \]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1You can picture those k, r , and v's being like 1,2, and 3's. They are just constants. You need your P's together and your t's together. I don't care and you shouldn't care where this puts the constants.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1You can actually leave k on the side it is on or divide both sides by k. It doesn't matter.

chikaa
 one year ago
Best ResponseYou've already chosen the best response.0this is what I got: \[P=\exp(\frac{ k }{ 2r }\sin(2rt2v)+\frac{ kt }{ 2 })\] However, this is what I should be getting according to the answer n my tutorial: \[P=\exp((\frac{ k }{ 2r }\sin(2rt2v)+\frac{ kt }{ 2 }\]\[+\frac{ k }{ 2r }\sin(2v))\]

chikaa
 one year ago
Best ResponseYou've already chosen the best response.0I don't get where the last bit came from

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1So did you set if up like I told you to?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{p} dp=k \cos^2(rtv) dt\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\lnp=k \int\limits_{}^{} \frac{1}{2}(\cos(2[rtv]+1) dt\]

chikaa
 one year ago
Best ResponseYou've already chosen the best response.0i'm just not getting the last bit k/2r sin(2v)

chikaa
 one year ago
Best ResponseYou've already chosen the best response.0help needed urgently!!!

KenLJW
 one year ago
Best ResponseYou've already chosen the best response.0dP/dt=kP cos(rtv)^2 dP/P=kcos(rtv)^2dt ln(P)=(k/3r)cos(rtv)^3 check with taking the Derivative with chain rule P=C1EXP[(k/3r)cos(rtv)^3
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