anonymous
  • anonymous
Couple of Question: Need Urgent Help! Solve: 2x2 + 7x + 3 = 0 Factor: 3x2 + 14x - 5 Factor: x2 + 14x + 24
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@DoYourHomework
anonymous
  • anonymous
|dw:1370029198878:dw|
anonymous
  • anonymous
Is the 1/2, negative?

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More answers

Jhannybean
  • Jhannybean
\[\large 2x^2+7x+3=0\]\[\large \color{red}{2}x^2+7x+\color{red}3\]\[\large x^2+7x+6\] two numbers that add to 7 and multiply to get 6\[\large (x+1)(x+6)\] divide by leading coefficient\[\large (x+\frac{ 1 }{ \color{red}2 })(x+\frac{ 6 }{ \color{red}{2} })\]\[\large (2x+1)(x+3)=0\]
Jhannybean
  • Jhannybean
now solve for each factor.
anonymous
  • anonymous
no its positive
anonymous
  • anonymous
{-1/2, -3} {1/2, 3} {-3/2, 1} {3/2, 1}
Jhannybean
  • Jhannybean
\[\large (2x+1)=0 \]\[x=-\frac{ 1 }{ 2 }\]\[\large (x+3)=0\]\[\large x=-3\] that's how you solve these types
anonymous
  • anonymous
|dw:1370029433777:dw|
anonymous
  • anonymous
sorry ya its negative 1/2
anonymous
  • anonymous
Ok thanks... :)
anonymous
  • anonymous
What about 2 and 3?
anonymous
  • anonymous
i have done 2nd one look to it
anonymous
  • anonymous
I can't really understand the writing ... But, It only looks like you done the 1st one.
anonymous
  • anonymous
(3x + 1)(x - 5) (3x - 1)(x + 5) (3x + 5)(x - 1) (3x - 5)(x + 1) Second question answers...
anonymous
  • anonymous
2nd ans (3x - 1)(x + 5) 3rd ans (x+12)(x=2)
Jhannybean
  • Jhannybean
\[\large 3x^2-14x-5\]\[\large \color{red}3x^2-14x-\color{red}5\]multiply the leading coefficient to the ending constant\[\large x^2-14x-15\] what two numbers add to get -14 and multiply to get -15? \[\large (x-15)(x+1)\]\[\large (x-\frac{ 15 }{ \color{red}3 })(x+\frac{ 1 }{ \color{red}3 })\] simplify \[\large (x-5)(3x+1)=0\] Solve for x.
anonymous
  • anonymous
Question 3 those are none of the answers... (x + 2)(x + 12) (x + 7)(x + 7) (x + 2)(x + 7) (x + 6)(x + 4)
Jhannybean
  • Jhannybean
@DEVESHkishore don't give answers directly...work out a problem.
anonymous
  • anonymous
(x+12)(x+2) see the 1st option
anonymous
  • anonymous
Thanks.... :) . I have a couple more... Could you guys help?
anonymous
  • anonymous
|dw:1370030076506:dw|
anonymous
  • anonymous
common lady greed is BAD.. you work we will helpy ou
anonymous
  • anonymous
x(x + 9) = 0
anonymous
  • anonymous
its simple you do it
anonymous
  • anonymous
{0, 1/9} {0, -9} {9} {0, 9} These are the answers... I think It's d. @DEVESHkishore
anonymous
  • anonymous
its b
Jhannybean
  • Jhannybean
stop giving answers!!!

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