anonymous
  • anonymous
4k^2-2k-5=0 Please Please Please help me??
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
reemii
  • reemii
wanna find the solutions i guess?
Luigi0210
  • Luigi0210
Have you tried synthetic division? c:
reemii
  • reemii
there's a formula for an equation in the form \(ax^2+bx +c=0\). (with the discriminant)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Luigi0210
  • Luigi0210
Oh, yea use the discriminant like @reemii says.. this will determine weather or not it will factor
anonymous
  • anonymous
Use the quadratic formula to solve the equation. I think its gonna be a fraction with square roots and stuff.
Luigi0210
  • Luigi0210
Have you tried it?
reemii
  • reemii
@kika_rayne yes, that one.
anonymous
  • anonymous
Tried what? Solving it? I dont even know where to start
anonymous
  • anonymous
|dw:1370031673895:dw|
anonymous
  • anonymous
I dont know what to do. omg im going to fail math! Today is my last day to get it to a passing grade and i have to go to work soon!! Thanks fo rtrying everyone
anonymous
  • anonymous
Wait is it 4 - or + 8? so like, -4, 12?
reemii
  • reemii
oops, link is bad
reemii
  • reemii
if the Δ=\(b^2-4ac>0\), there will be two solutions given by that formula with the fraction and root and all. if Δ=0 only one solution (same formula) if Δ<0 no solutions (no real numbers) as someone said, here \(a=4,b=-2,c=5\).
anonymous
  • anonymous
what does the triangle mean?
reemii
  • reemii
it's a symbol (delta) for the value called discriminant. it's usually noted like that.
anonymous
  • anonymous
ok, so what should i do? I really dont care about learning this, i just need to pass and i will study this summer
reemii
  • reemii
the answer to the question is a 2-step answer. 1) compute this \(\Delta\). 2) find the solutions (using the formula) in case there are. (that's something you must remember for your exams) here: 1. \(\Delta=b^2-4ac = (-2)^2 - 4 \times 4 \times (-5) = 4 + 16\times5 = 4+80=84\).
anonymous
  • anonymous
maybe this will help..idk
1 Attachment
reemii
  • reemii
2. Because \(\Delta>0\), there will be two solutions. the formula is \(-\frac{-b\pm\sqrt\Delta}{2a}\). first solution: \(-\frac{-b +\sqrt\Delta}{2a} = -\frac{-(-2) + \sqrt{84}}{2\times 4}\) second solution: \(-\frac{-b -\sqrt\Delta}{2a} = -\frac{-(-2) - \sqrt{84}}{2\times 4}\) you could make some simplifications in the fractions but that's not crucial.
reemii
  • reemii
oops, i made a mistake. remove all big minus signs in front of the fractions.
reemii
  • reemii
it should be first solution: \(\frac{-b +\sqrt\Delta}{2a} = \frac{-(-2) + \sqrt{84}}{2\times 4}\) second solution: first solution: \(\frac{-b -\sqrt\Delta}{2a} = \frac{-(-2) - \sqrt{84}}{2\times 4}\)
reemii
  • reemii
(so it's \(\frac{-b\pm\sqrt\Delta}{2a} \) for the general formula.) To get used to that method do at least 20 exercises, you'll memorize it easily.
anonymous
  • anonymous
-7.2/8 ?
reemii
  • reemii
oops, first solution: \(\frac{2+\sqrt{84}}{8}=1.39...\) second solution: \(\frac{2-\sqrt{84}}{8}=-0.8956...\)
anonymous
  • anonymous
Never mind. If i get wrong enough times, i get a new question. So i dont even have this question anymore because i got it wrong. Thanks @reemii and @physicsboffin @DEVESHkishore and @Luigi0210 anyway
Luigi0210
  • Luigi0210
I'm sorry D:
reemii
  • reemii
ohh -7.2/8 is right! it's one of the two solutions.
anonymous
  • anonymous
The answer was k = 1+[(sqr)21] 1-[(sqr)21] ______________ _____________ 4 4
reemii
  • reemii
yes, your answer is (1-sqrt(21))/4. they just didn't compute the value, instead they made simplifications.
anonymous
  • anonymous
Oh well, They gave me a new question anyways, but thanks for helping
reemii
  • reemii
11.2/8 is the other answer. you just didn't do it yet? don't get discouraged, you have found one of the two answers.!
reemii
  • reemii
solutions*
reemii
  • reemii
another quadratic equation?

Looking for something else?

Not the answer you are looking for? Search for more explanations.