anonymous
  • anonymous
PLZ HELP!!! See attachment.
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@Luis_Rivera so i'll take that as you don't know how to do it?
anonymous
  • anonymous
@amistre64 can you help with this?

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amistre64
  • amistre64
which part is giving you room to pause?
anonymous
  • anonymous
all of it
amistre64
  • amistre64
lets work on the test stat first, what do you recall about computing a tscore?
amistre64
  • amistre64
\[t=\frac{\bar x-\mu}{s}\sqrt n\]
anonymous
  • anonymous
oh ok i thought that was the formula but i wasn't sure.
amistre64
  • amistre64
#3 suggests that you recall something about hypt testing to begin with if we are looking for < or > its in a tail; if we are looking for =, its in both tails
anonymous
  • anonymous
When you say #3 you mean question c)?
amistre64
  • amistre64
part d, or #4 (i thought they was numbered) would suggest that the red is inbetween 2 values ...
anonymous
  • anonymous
for b) i did \[\frac{ 102.0-105 }{ \frac{ 5.8 }{ \sqrt{35} } }\] =-0.09
amistre64
  • amistre64
your setup is correct, but your calculation is off
anonymous
  • anonymous
i put it into mathway and it came out as 0.0874. so that makes it 0.09 right?
amistre64
  • amistre64
102-105 = -3 -3/5.8 = -0.51724 -0.51724 * sqrt(35) = -3.060...
anonymous
  • anonymous
so the answer would be -3.06?
amistre64
  • amistre64
thats what my ti83 gives me, yes
amistre64
  • amistre64
the standard deviation is 5.8/sqrt(35); or about .98 we are 3 to the left of center, giving us a little over -3 sds away
anonymous
  • anonymous
i'm getting something different. 102.0-105=-3 -3/5.8=-0.5172413793 -0.5172413793/sqrt(35)=-0.08742975049=-0.09
amistre64
  • amistre64
your not spose to divide that by sqrt(35)
amistre64
  • amistre64
\[\frac{a}{p/q}=\frac{a}{p}*q\]
amistre64
  • amistre64
if anything, 5.8/sqrt(35) = .98 -3/.98 = -3.06
anonymous
  • anonymous
ok i see that now.
amistre64
  • amistre64
part c has me a little confused, my book is stating a path: type of test? two tailed (since H0 not= H1 hyp) tstat to the left of right? ours is left since its negative therefore Pvalue = 2x the area to the left of the t score
amistre64
  • amistre64
its twice the area since its 2 tailed ... got it
anonymous
  • anonymous
so c) is B?
amistre64
  • amistre64
thats what i had originally considered, and thats what im going with :)
anonymous
  • anonymous
ok Is a) B?
amistre64
  • amistre64
my gut says no. but quite frankly i never was good at that kind of question. I want to say it yes, but cant really say why
anonymous
  • anonymous
well whats you're gut say it is?
amistre64
  • amistre64
my gut likes d, but its lied to me before :) on c, my book shows the pvalue area redshaded to the left, and says the pvalue is twice the area shaded ... which has me thinking that c is also just left shaded
anonymous
  • anonymous
then i will go with that. :)
anonymous
  • anonymous
now d)
amistre64
  • amistre64
how do you normally find the area? ti83 by chance?
anonymous
  • anonymous
no by hand or google
amistre64
  • amistre64
well, our zscore is -3.06 :) and we want the area to the left of it
anonymous
  • anonymous
so that would be...?
amistre64
  • amistre64
i thought you had indicated that you could find that area .... by hand or by google
amistre64
  • amistre64
http://www.danielsoper.com/statcalc3/calc.aspx?id=2
anonymous
  • anonymous
that's confusing. 1.25 means...?
amistre64
  • amistre64
1.25 is just a primer, our z score we found is -3.06 enter it into the box and hit calculate, it will give you the cumulative area up to z = -3.06
anonymous
  • anonymous
it gave me 0.00110668
amistre64
  • amistre64
im thinking that this is the lower bound, the area that is in the "red" we want to double that for an upper bound.
anonymous
  • anonymous
i'm thinking d) is A
amistre64
  • amistre64
...me too, but then again im only going off of what im reading in my stats book. if in reading it incorrectly, then i cant really guarentee the accuracy of my "guidance"
amistre64
  • amistre64
my ti83 gives a T-test, p-value of .004, which is not a range like the options .... nor is it really in the range of .001 to .002 ....
amistre64
  • amistre64
of course that next question has alot of 4s in it .004 * 1000 = 4
anonymous
  • anonymous
ok that means...?
amistre64
  • amistre64
at the moment, that means im conflicted between what the book says, and what the overall problem set is telling us. if p = .004, that would suggest that our range is between 002 and 005, but thats not the results i get from doing the process in the book. I simply dont have enough experience at this to know what, if anything, i am doing wrong :/
anonymous
  • anonymous
well whats your best guess?
anonymous
  • anonymous
i'd go with the book.
amistre64
  • amistre64
lol, the book doesnt jive with the next problem tho, so im thinking ive missed something. ti83 and the test stat by hand each give us -3.06 this should be the zscore value as well, unless there is some z to t adjustment that im missing
anonymous
  • anonymous
lol well i'll take a guess cause this problem is giving me a headache. lol
amistre64
  • amistre64
give me about 10 minutes to review a youtube :)
anonymous
  • anonymous
lol ok
amistre64
  • amistre64
got it
amistre64
  • amistre64
we should not have used the "normal" distribution with a t-score
amistre64
  • amistre64
when i use the tCDF, with 1 degree of freedom: tCDF(-9999,-3.06,35-1) = .00215 and doubled is .00430
anonymous
  • anonymous
?
amistre64
  • amistre64
in short, i assumed the t = z .... so our Pvalue is between .0021 and .0043
amistre64
  • amistre64
this will correspond to the next problem
anonymous
  • anonymous
so c) is C?
amistre64
  • amistre64
im going with C, yes :)
anonymous
  • anonymous
so to Interpret that it would be...?
amistre64
  • amistre64
well, to guide you to this, we just tested a mean of 102, and it has a Pvalue (probability value) of .4 % .... or .4 in every 100 how would you use this to determine (d) ?
amistre64
  • amistre64
if you expected to be paid: .004 cents for every hour you worked how much would you make in 10 hours? in 100? in 1000?
anonymous
  • anonymous
.004*10?
amistre64
  • amistre64
yes, so .04 cents for 10 hours ... and for 100?
anonymous
  • anonymous
0.4
amistre64
  • amistre64
good, 100 for .4 match an option? or do we need to go to 1000?
anonymous
  • anonymous
well 1000 is 4
amistre64
  • amistre64
so, its either B or C notice that the name on our little paycheck is "102" since thats what this Pvalue is attributed to
amistre64
  • amistre64
we should expect that in 1000 hours, mister 102 will be paid 4
anonymous
  • anonymous
so it's C?
amistre64
  • amistre64
gut says C :)
anonymous
  • anonymous
good now e)
amistre64
  • amistre64
(e) has to do with something im more familar with, a confidence interval
amistre64
  • amistre64
the area to reject the is termed alpha, that a looking thing
amistre64
  • amistre64
the expected value of a = .01 our pvalue is at best: .004 we rejecct the null hypotheses if the pvalue is less then or equal to the "a" value
anonymous
  • anonymous
so it's yes?
amistre64
  • amistre64
correct
anonymous
  • anonymous
Great! got time to help with 1 more short question?
amistre64
  • amistre64
not really, i have to be heading home.
anonymous
  • anonymous
lol ok thx for the help!
amistre64
  • amistre64
good luck with this :)
anonymous
  • anonymous
THX!

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