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karniyax Group Title

nPr=3024,then how to calculate the value of r?

  • one year ago
  • one year ago

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  1. DanielM_113 Group Title
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    Same question asked here http://openstudy.com/updates/50df347fe4b0f2b98c87319f

    • one year ago
  2. UnkleRhaukus Group Title
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    \[^nP_r=\frac{n!}{(n-r)!}\]

    • one year ago
  3. UnkleRhaukus Group Title
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    Permutation

    • one year ago
  4. matricked Group Title
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    first factorise 3024

    • one year ago
  5. matricked Group Title
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    find the highest prime factor number in the factors here we are having 3024 = 7*3*3*3 *2*2*2*2 either start from the leading prime factor or form consecutive sequence of the factors obtained

    • one year ago
  6. matricked Group Title
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    here we are having 3024 = 9*8*7*6

    • one year ago
  7. matricked Group Title
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    3024 = 9*8*7*6*5! /5!= 9!/(9-4)!

    • one year ago
  8. matricked Group Title
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    r=4

    • one year ago
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