anonymous
  • anonymous
.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jim_thompson5910
  • jim_thompson5910
There are 12 numbers total: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
jim_thompson5910
  • jim_thompson5910
Of this list of numbers, which are perfect squares?
anonymous
  • anonymous
Ummm... 1, 4, 9?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
so there are 3 perfect squares out of 12 total the probability is 3/12 = 1/4
jim_thompson5910
  • jim_thompson5910
ie you have a 1 in 4 chance (25% chance) of rolling a perfect square
anonymous
  • anonymous
Okay! :) So.. Im confused about the nearest tenth part then. Or is that 25?
jim_thompson5910
  • jim_thompson5910
what you do for the next part is add up the numbers from 1 to 12 then you divide by 12
anonymous
  • anonymous
Thats all?
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
Okay, thank you so much! :) So.. this is grade 12 math... are there any special formula's I should be using? Or is it simply that? 1/4?
jim_thompson5910
  • jim_thompson5910
you're just using the idea that P(event A happening) = (# of ways for event A to happen)/(# of ways total)
anonymous
  • anonymous
OH So P(a) = 1/4?
jim_thompson5910
  • jim_thompson5910
and expected value is E[X] = sum of x*p where x = value p = probability of that value x of occuring
anonymous
  • anonymous
Ohhhh. Okay! I see now. Thanks!!
jim_thompson5910
  • jim_thompson5910
I would stick to 1/4 and don't worry about the P(a) part
anonymous
  • anonymous
Okay, Thanks! :)
jim_thompson5910
  • jim_thompson5910
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.