anonymous
  • anonymous
If 2.0 × 10^-4 C of charge passes a point in 5.0 × 10^-6 s, what is the rate of current flow? You plug a string of 100 lights in series into a 120 V power outlet, and each light has a resistance of 3.00 Ω. If each light has a power rating of 0.50 W, what will happen?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ChillOut
  • ChillOut
This is not mathematics. But anyway: \[I = \frac{dq}{dt} \rightarrow I =\frac{2*10^{-4}}{5*10^{-6}} = 0.4*10² = 40 C/s \ (Ampères) \]
ChillOut
  • ChillOut
Now for the second question...
ChillOut
  • ChillOut
Using Ohm's law, we have\[120 =(100*3)I,\ \ I = 0.4\ A\] Using the voltage divider rule, each lamp will have a voltage drop of 120/100 = 1.2 V. Calculating the dissipated energy, we have P=RI²\[P = 1.2*0.4=0.48W\] The lamps will not burn out.

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ChillOut
  • ChillOut
Oops, the dissipated energy in this line "Calculating the dissipated energy, we have P=RI²" should be P=VI. But it can be done like that too.
anonymous
  • anonymous
So for the first question, this; 4.0 × 10^-1 A would be the answer?
ChillOut
  • ChillOut
No. 4.0 * 10 A, 40* 10^0 A or 0.4 * 10 A
ChillOut
  • ChillOut
I mean, 0.4 * 100 A
anonymous
  • anonymous
But the options I'm given are: 4.0 × 10^-1 A 4.0 × 10^1 A 1.0 × 10^-10 A 1.0 × 10^2 A
ChillOut
  • ChillOut
It's the second option! Remember that 10^1 is 10, 10^-1 = 1/10, 10^-2 = 1/10², and so on...
anonymous
  • anonymous
Ohhh, okay! Thanks so much

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