anonymous
  • anonymous
what values for theta (0< theta < 2pi) satisfy the equation 2 cos theta + 1 = -cos theta
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Loser66
  • Loser66
@Luigi0210
Luigi0210
  • Luigi0210
\[2\cos \theta+1=-\cos \theta\] Move all to one side\[3\cos \theta=-1\] \[\cos \theta=-\frac{ 1 }{ 3 }\]
Luigi0210
  • Luigi0210
I don't know if that's right..

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anonymous
  • anonymous
\[2 \cos \theta + 1 = - \cos \theta\] \[3 \cos \theta = -1\]\[\cos \theta = -\frac{ 1 }{ 3 }\]\[\theta = \cos^{-1} -\frac{ 1 }{ 3 }\] \[\cos \theta < 0 \] therefore is in the second and third quadrant Use the reference angle given by : \[\theta _{r}= \cos^{-1} \frac{ 1 }{ 3}\] Then you have two solution \[\pi - \theta _{r}\] and \[\pi + \theta _{r}\]
anonymous
  • anonymous
so 0 and 3.14?
Luigi0210
  • Luigi0210
It's whatever theta is -/+ pi, like vel showed
anonymous
  • anonymous
im confused.
anonymous
  • anonymous
Because θr is not a special case angle like 30,45,60,90 etc you need a calculator to get the number
anonymous
  • anonymous
Im so confused with thi questions lol sorry guys maybe because im a little sleep..
anonymous
  • anonymous
sleepy*
anonymous
  • anonymous
\[\cos^{-1} \frac{ 1 }{ 3 }=1.23\] \[\pi =3.14\] 3.14 - 1.23 3.14 + 1.23

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