anonymous
  • anonymous
Please help, I will give medal and become a fan if the answer is correct
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Given: Line segment AB is perpendicular to line segment FC Line segment DE is perpendicular to line segment FC line segment AB is congruent to line segment DE ∠DEF ≅ ∠BAC Statement Reason Line segment AB is perpendicular to line segment FC Line segment DE is perpendicular to line segment FC line segment AB is congruent to line segment DE ∠DEF ≅ ∠BAC Given ∠FDE = 90˚ and ∠ABC = 90˚ Definition of Perpendicular Lines ∠FDE ≅ ∠ABC Substitution ΔABC ≅ ΔEDF Angle-Side-Angle Which figure correctly displays this proof?
anonymous
  • anonymous
anonymous
  • anonymous

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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
Hint: It's given that AB is perpendicular to FC
jim_thompson5910
  • jim_thompson5910
so this means that AB and FC a) connect, intersect, or touch b) they meet at right angles (or 90 degree angles)
anonymous
  • anonymous
Last one?
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
that's the only one that fits the descriptions I posted
anonymous
  • anonymous
Can u help me with some more please ill medal and thanks
jim_thompson5910
  • jim_thompson5910
ok a few more
anonymous
  • anonymous
Which of the following statements will guarantee that ΔZWU ≅ ΔVUW? Quadrilateral ZWVU is a square. Line segment ZW is parallel to line segment UV ∡ZUV and ∡WVU measure 90°. Line segment ZU ≅ Line segment WV
anonymous
  • anonymous
anonymous
  • anonymous
soo?
jim_thompson5910
  • jim_thompson5910
one sec
anonymous
  • anonymous
ok no prob
jim_thompson5910
  • jim_thompson5910
If you were to divide a square by it's diagonal, what would you get
anonymous
  • anonymous
two triangles
anonymous
  • anonymous
right
jim_thompson5910
  • jim_thompson5910
what kind of triangles
anonymous
  • anonymous
so now what?
jim_thompson5910
  • jim_thompson5910
what kind of triangles form
anonymous
  • anonymous
right ones
jim_thompson5910
  • jim_thompson5910
are they congruent triangles
anonymous
  • anonymous
oh ya
jim_thompson5910
  • jim_thompson5910
how do you know
anonymous
  • anonymous
So now that we've established that, what now?
jim_thompson5910
  • jim_thompson5910
well those two triangles are congruent (you can use the SSS property to show it's true) so that guarantees you'll have 2 congruent triangles
anonymous
  • anonymous
What answer choice should I choose because that's not a choice
jim_thompson5910
  • jim_thompson5910
what shape did we start with
anonymous
  • anonymous
square
jim_thompson5910
  • jim_thompson5910
so dividing up a square along its diagonal guarantees you'll have 2 congruent triangles
anonymous
  • anonymous
so A?
jim_thompson5910
  • jim_thompson5910
correct, that's one way to guarantee you'll get those 2 triangles to be congruent
anonymous
  • anonymous
OK can I ask a few more there simple as you can see
jim_thompson5910
  • jim_thompson5910
alright 2 more
anonymous
  • anonymous
Which fact could you use to help prove that ΔAEDΔBEC using Side-Angle-Side? Line segment AD is parallel to line segment CB. Line segment CE over line segment DE is equal to line segment BE over line segment AE. The measure of line segment CE is equal to one-third times the measure of line segment DE. Line segment AD is congruent to line segment CB.
anonymous
  • anonymous
Which fact could you use to help prove that ΔAEDΔBEC using Side-Angle-Side? Line segment AD is parallel to line segment CB. Line segment CE over line segment DE is equal to line segment BE over line segment AE. The measure of line segment CE is equal to one-third times the measure of line segment DE. Line segment AD is congruent to line segment CB.
anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
whenever you use the SAS similarity postulate, you use the idea that the sides are proportional to each other
jim_thompson5910
  • jim_thompson5910
so what does that mean
anonymous
  • anonymous
They are similar
anonymous
  • anonymous
so now what?
jim_thompson5910
  • jim_thompson5910
if two triangles are similar, then the corresponding sides form a ratio
anonymous
  • anonymous
so option B?
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
OK :) last one
anonymous
  • anonymous
1.For the dilation, what was your scale factor? 2.For the reflection, across which line did you reflect it? 3.For the rotation, how many degrees was it rotated and in which direction?
anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
I know the labels are wrong I already fixed the reflection and 180 degree counterclockwise turn
jim_thompson5910
  • jim_thompson5910
what's your question about this one
anonymous
  • anonymous
1.For the dilation, what was your scale factor? 2.For the reflection, across which line did you reflect it? 3.For the rotation, how many degrees was it rotated and in which direction?
jim_thompson5910
  • jim_thompson5910
you have the dilation labeled on your paper
jim_thompson5910
  • jim_thompson5910
the scale factor of the dilation
jim_thompson5910
  • jim_thompson5910
the rotation you have is incorrect
anonymous
  • anonymous
I know I told u I fixed that
anonymous
  • anonymous
how do I find the scale factor for the dilation
jim_thompson5910
  • jim_thompson5910
you already found it, it's 2
anonymous
  • anonymous
Ok next question lol
anonymous
  • anonymous
O must be losing my eyes lol
jim_thompson5910
  • jim_thompson5910
if you were to rotate the original figure 180 degrees, it won't go from Q1 to Q4
anonymous
  • anonymous
I fixed that already.How do I find out which line I reflected the image over.
jim_thompson5910
  • jim_thompson5910
ok, the reflected image is in Q4 right?
anonymous
  • anonymous
The image that I wrote was rotated is actually reflected, and the other new figure next to it was a 180 degree turn counterclockwise from the original
jim_thompson5910
  • jim_thompson5910
i see
jim_thompson5910
  • jim_thompson5910
so they're flipped
anonymous
  • anonymous
Would that be correct?
jim_thompson5910
  • jim_thompson5910
you're reflecting over the x-axis which is the line y = 0
jim_thompson5910
  • jim_thompson5910
yes that's correct
anonymous
  • anonymous
So what do I write. I reflected over line y=0?
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
Thank You I wish u could help me more but a deal is a deal.
jim_thompson5910
  • jim_thompson5910
hopefully you can use the info learned here to apply it to the others I don't want to do it all for you
anonymous
  • anonymous
OK :) Thanks have a good night
jim_thompson5910
  • jim_thompson5910
yw, you too

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