Please help, I will give medal and become a fan if the answer is correct

- anonymous

Please help, I will give medal and become a fan if the answer is correct

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- anonymous

Given:
Line segment AB is perpendicular to line segment FC
Line segment DE is perpendicular to line segment FC
line segment AB is congruent to line segment DE
∠DEF ≅ ∠BAC
Statement
Reason
Line segment AB is perpendicular to line segment FC
Line segment DE is perpendicular to line segment FC
line segment AB is congruent to line segment DE
∠DEF ≅ ∠BAC
Given
∠FDE = 90˚ and ∠ABC = 90˚
Definition of Perpendicular Lines
∠FDE ≅ ∠ABC
Substitution
ΔABC ≅ ΔEDF
Angle-Side-Angle
Which figure correctly displays this proof?

- anonymous

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- anonymous

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## More answers

- anonymous

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- anonymous

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- anonymous

@jim_thompson5910

- jim_thompson5910

Hint:
It's given that AB is perpendicular to FC

- jim_thompson5910

so this means that AB and FC
a) connect, intersect, or touch
b) they meet at right angles (or 90 degree angles)

- anonymous

Last one?

- jim_thompson5910

good

- jim_thompson5910

that's the only one that fits the descriptions I posted

- anonymous

Can u help me with some more please ill medal and thanks

- jim_thompson5910

ok a few more

- anonymous

Which of the following statements will guarantee that ΔZWU ≅ ΔVUW?
Quadrilateral ZWVU is a square.
Line segment ZW is parallel to line segment UV
∡ZUV and ∡WVU measure 90°.
Line segment ZU ≅ Line segment WV

- anonymous

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- anonymous

soo?

- jim_thompson5910

one sec

- anonymous

ok no prob

- jim_thompson5910

If you were to divide a square by it's diagonal, what would you get

- anonymous

two triangles

- anonymous

right

- jim_thompson5910

what kind of triangles

- anonymous

so now what?

- jim_thompson5910

what kind of triangles form

- anonymous

right ones

- jim_thompson5910

are they congruent triangles

- anonymous

oh ya

- jim_thompson5910

how do you know

- anonymous

So now that we've established that, what now?

- jim_thompson5910

well those two triangles are congruent (you can use the SSS property to show it's true)
so that guarantees you'll have 2 congruent triangles

- anonymous

What answer choice should I choose because that's not a choice

- jim_thompson5910

what shape did we start with

- anonymous

square

- jim_thompson5910

so dividing up a square along its diagonal guarantees you'll have 2 congruent triangles

- anonymous

so A?

- jim_thompson5910

correct, that's one way to guarantee you'll get those 2 triangles to be congruent

- anonymous

OK can I ask a few more there simple as you can see

- jim_thompson5910

alright 2 more

- anonymous

Which fact could you use to help prove that ΔAEDΔBEC using Side-Angle-Side?
Line segment AD is parallel to line segment CB.
Line segment CE over line segment DE is equal to line segment BE over line segment AE.
The measure of line segment CE is equal to one-third times the measure of line segment DE.
Line segment AD is congruent to line segment CB.

- anonymous

- anonymous

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- jim_thompson5910

whenever you use the SAS similarity postulate, you use the idea that the sides are proportional to each other

- jim_thompson5910

so what does that mean

- anonymous

They are similar

- anonymous

so now what?

- jim_thompson5910

if two triangles are similar, then the corresponding sides form a ratio

- anonymous

so option B?

- jim_thompson5910

correct

- anonymous

OK :) last one

- anonymous

1.For the dilation, what was your scale factor?
2.For the reflection, across which line did you reflect it?
3.For the rotation, how many degrees was it rotated and in which direction?

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- anonymous

@jim_thompson5910

- anonymous

I know the labels are wrong I already fixed the reflection and 180 degree counterclockwise turn

- jim_thompson5910

what's your question about this one

- anonymous

1.For the dilation, what was your scale factor?
2.For the reflection, across which line did you reflect it?
3.For the rotation, how many degrees was it rotated and in which direction?

- jim_thompson5910

you have the dilation labeled on your paper

- jim_thompson5910

the scale factor of the dilation

- jim_thompson5910

the rotation you have is incorrect

- anonymous

I know I told u I fixed that

- anonymous

how do I find the scale factor for the dilation

- jim_thompson5910

you already found it, it's 2

- anonymous

Ok next question lol

- anonymous

O must be losing my eyes lol

- jim_thompson5910

if you were to rotate the original figure 180 degrees, it won't go from Q1 to Q4

- anonymous

I fixed that already.How do I find out which line I reflected the image over.

- jim_thompson5910

ok, the reflected image is in Q4 right?

- anonymous

The image that I wrote was rotated is actually reflected, and the other new figure next to it was a 180 degree turn counterclockwise from the original

- jim_thompson5910

i see

- jim_thompson5910

so they're flipped

- anonymous

Would that be correct?

- jim_thompson5910

you're reflecting over the x-axis
which is the line y = 0

- jim_thompson5910

yes that's correct

- anonymous

So what do I write. I reflected over line y=0?

- jim_thompson5910

yep

- anonymous

Thank You I wish u could help me more but a deal is a deal.

- jim_thompson5910

hopefully you can use the info learned here to apply it to the others
I don't want to do it all for you

- anonymous

OK :) Thanks have a good night

- jim_thompson5910

yw, you too

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