anonymous
  • anonymous
Solve the linear system. 15x + 10y = 145 and 4x - 6y = 56
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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johnweldon1993
  • johnweldon1993
You can use either the elimination method, or the substitution method here to solve these...
Jhannybean
  • Jhannybean
Solve 1 equation for y first. \[\large 4x-6y=56 \to y= \frac{ -4x+56 }{ -6 } = \frac{ 2 }{ 3 }x-\frac{ 28 }{ 3 }\]\] use this to plug into the other equation to solve for one variable.\[\large 15x+10(\frac{ 2 }{ 3 }x-\frac{ 28 }{ 3 })=145\]\[\large 15x+\frac{ 20 }{ 3 }x-\frac{ 280 }{ 3 }=145\]\[\large \frac{ 65 }{ 3 }x=\frac{ 715 }{ 3 }\]\[x=\frac{ 715 }{ 3 }*\frac{ 3 }{ 65}=11\] So we found x, then plug "x=11" back into any equation to solve for y, you will have both of your variables :)
anonymous
  • anonymous
solution: x = 11, y= -2 -------------------------------------------------- 150 x y = 145

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Jhannybean
  • Jhannybean
ok? I wasn't giving solutions, just trying to help the person work out the problem, but thanks.
anonymous
  • anonymous
Oh sorry haha
Jhannybean
  • Jhannybean
Alrighty.
anonymous
  • anonymous
thanks both of you
anonymous
  • anonymous
i like the solution part tho haha
Jhannybean
  • Jhannybean
You mean the answers.
anonymous
  • anonymous
No problemo haha

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