Need geometry help. The equation of a circle is (x + 6)2 + (y + 2)2 = 16. The point (-6, 2) is on the circle.
What is the equation of the line that is tangent to the circle at (-6, 2)?

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I suppose you mean \((x+ 6)^2 + (y+2)^2 = 16\), correct?

yes

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