anonymous
  • anonymous
truth table (qv~r)<->(p^~q)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Jhannybean
  • Jhannybean
define what Q, R, and P are first?
anonymous
  • anonymous
p t t t t f f f f q t t f f t t f f r t f t f t f t f
anonymous
  • anonymous
~r f t f t f t f t ~q f f t t f f t t

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anonymous
  • anonymous
now what???????
Loser66
  • Loser66
suggestion: arrange those in horizontal like |dw:1370142222437:dw|
Loser66
  • Loser66
step by step you can construct the truth table for the last one(what you need)
Loser66
  • Loser66
for example, at the column of (q v~r) you just consider the combination between column q and column ~r , when you see one of them has value t, the (qv~r) has value t .got what i mean?
anonymous
  • anonymous
yes
anonymous
  • anonymous
so q v ~r is t for the first one
Loser66
  • Loser66
yes
Loser66
  • Loser66
be careful, the order of value of them is very important, they may be not the same between yours and mine. So, come up with yours only. I 'll show you mine to compare only
Loser66
  • Loser66
hey, many smarties here, you are safe, I can stay aside to see, ok?
anonymous
  • anonymous
okthank you
Jhannybean
  • Jhannybean
the <-> means if and only if.I believe...
Loser66
  • Loser66
@Jhannybean you are right, and we have a rule for that , too
anonymous
  • anonymous
yeah thats what i dont get is how to imply that into the t/f concept
Jhannybean
  • Jhannybean
The stuff on the right can ONLY be true if the stuff on the left is true.That symbol is your main function.
Jhannybean
  • Jhannybean
( all your functions here ) are true, ONLY THEN are (all the things on the right) true.
anonymous
  • anonymous
so if its q v not r the q is true and the not r is false will it be true
anonymous
  • anonymous
i will draw what i came up with
Jhannybean
  • Jhannybean
|dw:1370143095993:dw|
Loser66
  • Loser66
@Jhannybean be careful, at p iff q, when both them are false, the result is true
Loser66
  • Loser66
I mean: 1 <---> 2 , if both 1 and 2 true the whole thing is true , and if both them are false, the whole thing is TRUE
anonymous
  • anonymous
|dw:1370143121408:dw|
anonymous
  • anonymous
@Jhannybean
Loser66
  • Loser66
(q~r ) recheck row 3,4,7
Loser66
  • Loser66
(p^~q) recheck row 1,2.
Loser66
  • Loser66
|dw:1370144081731:dw|
Loser66
  • Loser66
you still have the last column to get the final answer,
anonymous
  • anonymous
yeah thats where im lost
Loser66
  • Loser66
ok, I checked and since "someone else" ( who stands there and watch) says nothing, I think mine is ok, continue, friend, last column
anonymous
  • anonymous
Yes it's fine. If you are confused about the implication in both directions (if and only if) it is just an equivalence.
anonymous
  • anonymous
Check your final answers against wolfram alpha: http://www.wolframalpha.com/input/?i=%28q+or+not+r%29+equivalent+%28p+and+not+q%29
Loser66
  • Loser66
I have the table for iff here, lol https://www.google.com/search?q=truth+tables&tbm=isch&tbo=u&source=univ&sa=X&ei=xLmqUcn5FauJ0QGlt4DwBg&sqi=2&ved=0CDUQsAQ&biw=1440&bih=696#fa
anonymous
  • anonymous
ok but istill dont know what to do
Loser66
  • Loser66
@Alchemista Please, we don't have math tool on test. teach him how to get
anonymous
  • anonymous
It is a predicate based on equivalence T = T (does true equal true, yes so true). T = F (does true equal false, no, so false). F = T (not equal, so false) F = F (equal, so true)
anonymous
  • anonymous
omg thank you
anonymous
  • anonymous
So the final column is checking the equivalence of the two columns before it.
Loser66
  • Loser66
Thank you

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