truth table (qv~r)<->(p^~q)

- anonymous

truth table (qv~r)<->(p^~q)

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- chestercat

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- Jhannybean

define what Q, R, and P are first?

- anonymous

p t t t t f f f f
q t t f f t t f f
r t f t f t f t f

- anonymous

~r f t f t f t f t
~q f f t t f f t t

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## More answers

- anonymous

now what???????

- Loser66

suggestion: arrange those in horizontal like |dw:1370142222437:dw|

- Loser66

step by step you can construct the truth table for the last one(what you need)

- Loser66

for example, at the column of (q v~r) you just consider the combination between column q and column ~r , when you see one of them has value t, the (qv~r) has value t .got what i mean?

- anonymous

yes

- anonymous

so q v ~r is t for the first one

- Loser66

yes

- Loser66

be careful, the order of value of them is very important, they may be not the same between yours and mine. So, come up with yours only. I 'll show you mine to compare only

- Loser66

hey, many smarties here, you are safe, I can stay aside to see, ok?

- anonymous

okthank you

- Jhannybean

the <-> means if and only if.I believe...

- Loser66

@Jhannybean you are right, and we have a rule for that , too

- anonymous

yeah thats what i dont get is how to imply that into the t/f concept

- Jhannybean

The stuff on the right can ONLY be true if the stuff on the left is true.That symbol is your main function.

- Jhannybean

( all your functions here ) are true, ONLY THEN are (all the things on the right) true.

- anonymous

so if its q v not r the q is true and the not r is false will it be true

- anonymous

i will draw what i came up with

- Jhannybean

|dw:1370143095993:dw|

- Loser66

@Jhannybean be careful, at p iff q, when both them are false, the result is true

- Loser66

I mean: 1 <---> 2 , if both 1 and 2 true the whole thing is true , and if both them are false, the whole thing is TRUE

- anonymous

|dw:1370143121408:dw|

- anonymous

@Jhannybean

- Loser66

(q~r ) recheck row 3,4,7

- Loser66

(p^~q) recheck row 1,2.

- Loser66

|dw:1370144081731:dw|

- Loser66

you still have the last column to get the final answer,

- anonymous

yeah thats where im lost

- Loser66

ok, I checked and since "someone else" ( who stands there and watch) says nothing, I think mine is ok, continue, friend, last column

- anonymous

Yes it's fine. If you are confused about the implication in both directions (if and only if) it is just an equivalence.

- anonymous

Check your final answers against wolfram alpha: http://www.wolframalpha.com/input/?i=%28q+or+not+r%29+equivalent+%28p+and+not+q%29

- Loser66

I have the table for iff here, lol https://www.google.com/search?q=truth+tables&tbm=isch&tbo=u&source=univ&sa=X&ei=xLmqUcn5FauJ0QGlt4DwBg&sqi=2&ved=0CDUQsAQ&biw=1440&bih=696#fa

- anonymous

ok but istill dont know what to do

- Loser66

@Alchemista Please, we don't have math tool on test. teach him how to get

- anonymous

It is a predicate based on equivalence
T = T (does true equal true, yes so true).
T = F (does true equal false, no, so false).
F = T (not equal, so false)
F = F (equal, so true)

- anonymous

omg thank you

- anonymous

So the final column is checking the equivalence of the two columns before it.

- Loser66

Thank you

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