anonymous
  • anonymous
determine if the lines in each pair intersect. if so, find the coordinates of the point of intersection. [x,y,z]=[6,5,-14]+s[-1,1,3] [x,y,z]=[11,0,-17]+t[4,-1,-6]
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Rewrite it as a linear system of equations and solve.
anonymous
  • anonymous
I wrote the parametric equations for both lines and set them equal to each other. I got t=0 and s=-5. But my book says that there is no answer since the lines can't intersect. The lines are not parallel.
anonymous
  • anonymous
They need not be parallel. This is 3-space not 2-space

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
they are not parallel tho. but how cant I know if they intersect or not?
anonymous
  • anonymous
As I said, rewrite it as a system of equations. If there is no solution then they do not intersect.
anonymous
  • anonymous
i did write them, and I did solve them and when I isolated for t and s, i got 0 and -5. but my book says they don't intersect
anonymous
  • anonymous
ummm whats that???
anonymous
  • anonymous
This isn't a linear algebra class?
anonymous
  • anonymous
no
anonymous
  • anonymous
this is a high school class and the only thing I have learned so far about this is parametric equation, vector equation, and standard equation
anonymous
  • anonymous
Well you must have made a mistake when you attempted to solve the system by substitution/elimination or whatever you did. Since there is no solution.
anonymous
  • anonymous
the way my book does it is that they give parallel lines and they find the parametric equation, then they sub the point from the first equation into the second and see if its distinct or coincident. Then they use substitution and find that they don't intersect.
anonymous
  • anonymous
Yes, but I'm trying to tell you this is the same as trying to solve a system of linear equations. I'm sure you've done this before in school.
phi
  • phi
in 3D, two lines need not be parallel to not intersect |dw:1370193299759:dw| notice that with t=0 and s=-5 you get the points [11,0,-17]+t[4,-1,-6]= [11,0,-17] and [6,5,-14]+s[-1,1,3]= [6,5,-14]+[5,-5,-15]= [ 11,0,-29] though the points share the same x and y coordinates, their z coordinates do not match. the lines never meet.

Looking for something else?

Not the answer you are looking for? Search for more explanations.