anonymous
  • anonymous
How do you find the derivative of: (x^3 -3x^2 + 4) / x^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[ (x^3 -3x^2 + 4) \div x^2\]
anonymous
  • anonymous
I get, 1-8x^-3... so 1/-8x^3 Answer is x^3 - 8 / x^3
.Sam.
  • .Sam.
You just split them \[\frac{ x^3 -3x^2 + 4 }{ x^2 } \\ \\ \\ \\ \frac{x^3}{x^2}-\frac{3x^2}{x^2}+\frac{4}{x^2} \\ \\ x-3+\frac{4}{x^2}\] Then use power rule

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.Sam.
  • .Sam.
\[\frac{d}{dx}x^n=nx^{n-1}\]
anonymous
  • anonymous
That's exactly what I did.. \[1 - 8x^-3\]
.Sam.
  • .Sam.
Your problem is on differentiating \[\frac{4}{x^2}\]
anonymous
  • anonymous
that becomes (4) (-2x^-3)
.Sam.
  • .Sam.
Careful, put it like this first \[\frac{4}{x^2} \\ \\ =4x^{-2}\] Then use power rule
.Sam.
  • .Sam.
You get \(-8x^{-3}\)
anonymous
  • anonymous
Yes
.Sam.
  • .Sam.
Putting it all together \(1-8x^{-3}\)
anonymous
  • anonymous
Yeeah, thats what I got 1-8x^-3
anonymous
  • anonymous
Nvm... Got it.. 1 becomes x^3 / x^3

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