anonymous
  • anonymous
Using the quadratic formula how would one solve 5x^2 -4px-p^2= 0 [i'm really confused by the two powers; shouldn't there only be one in a quadratic pattern]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[5x^2-4px-p^2\]
anonymous
  • anonymous
\[b ^{2}-4ac=0\] a=5, b=-4p, c=-p^2
anonymous
  • anonymous
use quadratic formula to solve the p

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anonymous
  • anonymous
So you solve for p and x seperatley
anonymous
  • anonymous
the question want to find p right?
anonymous
  • anonymous
Solve for x
anonymous
  • anonymous
use factorisation (-5x-p)(-1x+p)=0
anonymous
  • anonymous
here you are required to factorise to solve for x ..good job @jckm135
anonymous
  • anonymous
But it says use quadratic formula
anonymous
  • anonymous
honestly i've never used the quadratic formula for this type of example
anonymous
  • anonymous
ill try wolfram alpha, thanks anyway
helder_edwin
  • helder_edwin
when u have an expression like this u have to ask which of the two letters is your unknown
anonymous
  • anonymous
if anyone is interested http://i.imgur.com/GsybwCP.png
ganeshie8
  • ganeshie8
p is constant, x is variable here
helder_edwin
  • helder_edwin
if the unknown is x then your equation is \[ \large \color{red}{5}x^2\color{red}{-4p}x\color{red}{-p^2}=0 \] and the quadratic formula gives you the solutions \[ \large x=\frac{-(-4p)\pm\sqrt{(-4p)^2-4(5)(-p^2)}}{2(5)} \]
helder_edwin
  • helder_edwin
got it? and yes, as ganeshie8 points out, it is traditional for x to be the unknown and any other letter to be a constant
anonymous
  • anonymous
Yeah thanks a lot i think i just got a bit lost when i was adding the like terms

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