anonymous
  • anonymous
Find the point on the curve
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[y=\frac{ x }{ x ^{2}+1 }\] where \[\frac{ dy }{ dx }=0\] and sketch the graph of this curve.
anonymous
  • anonymous
have you graphed the curve yet?
anonymous
  • anonymous
@radar

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reemii
  • reemii
do you know how to compute the derivative ?
anonymous
  • anonymous
i got x*arctan(x)+1/(x^2+1) but im not sure
reemii
  • reemii
nope. use the formula for the derivative of a quotient \((f/g)'\). the answer is has no arctan in it.
anonymous
  • anonymous
(1-x^2)/(x^2+1)^2
reemii
  • reemii
right
anonymous
  • anonymous
what about point?
reemii
  • reemii
it says where "(f/g)' = 0" . you just computed (f/g)' . now solve the equation.
anonymous
  • anonymous
but i'll contradict the answer
anonymous
  • anonymous
x^2+1 cannot be equal zero
anonymous
  • anonymous
x cannot be +or -1
anonymous
  • anonymous
but, in the answer it is
reemii
  • reemii
the numerator is 1-x^2. not 1+x^2.
anonymous
  • anonymous
i'm about denominator
anonymous
  • anonymous
that is x^2+1 in squares
reemii
  • reemii
but you don't care about the denominator. \(\frac AB = 0 \iff A=0\). you only have to solve for the numerator.
anonymous
  • anonymous
mmmmmmm mhhmmmm mhhhhhhhhhhhhhhhhhmmm thanks :DD
reemii
  • reemii
the two points are x=±1.

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