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so we use partial fractions?
ya use partial fraction
i'm not sure, i think it can be done without aswell
take long division first.
@Luigi0210 are you with me?
ok, wait until the Asker responds.
what am i supposed to be doing? :P i got this:
@Luigi0210 knock knock
Let x=1, A=-4 Let x =2, B=9
Who's there? and that's what I ended up with too but I haven't done partial fractions in a while
ok awesome, where does the 1+ come from?
\[f(x) = -4/(x-1) + 9/(x-2)\]
yay or nay?
|dw:1370189894575:dw| doing this...you are saying a quadratic function is equal to a linear function
I would of never guessed that..
@RadEn what did u do to line 2?
to get the 1 :)
OH I SEE IT!!!! thank you!!
still dont entirely see why my solution doesn't work?
apart from the fact that...it doesnt work....why is it wrong? thought you could do that with partial fractions?
ok i think i understand :) thank you so much :)
(5x-1)/(x^2-3x+2) = A/(x-1) + B(x-2)
so that can be done because its linear on top
is it do with rationality?
Aha..."a proper rational function is one in which the degree of the numerator is less than the denominator" so a partial fraction must be proper to be solved. Thank you everyone <3
This has been one the best solution threads I read in a long time. I wish I could award medals to all that participated.