Summersnow8
  • Summersnow8
Find exact values for this trig function: sec (pi/6) I know that sec is cos (6/pi), but I don't understand how you get 2/ square root (3)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Luigi0210
  • Luigi0210
|dw:1370190117985:dw|
Summersnow8
  • Summersnow8
gotcha! thanks!
Luigi0210
  • Luigi0210
Any time

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Summersnow8
  • Summersnow8
wait that makes no sense..... @Luigi0210 |dw:1370190374799:dw|
anonymous
  • anonymous
Whoa! sec(pi/6) is not equal to cos(6/pi). sec(pi/6)= 1/cos(pi/6).
anonymous
  • anonymous
plz help The owner of a large company is conducting a survey about job satisfaction, including questions about salary, hours, stress, and other conditions. There are about 800 employees in the company, including 100 executive positions, 650 middle-management positions, and 50  custodial positions. The owner wants to include about 10% of his employees in the survey sample.  Identify a sampling method that would lead to a representative sample for the survey. Explain why it would be a good choice and give details about the process.
Luigi0210
  • Luigi0210
open a new question dude :/
Summersnow8
  • Summersnow8
@kutabs my teacher said it means the same thing..... but i dont know how 2/ sqrt 3 is the answer
Luigi0210
  • Luigi0210
technically they are in a way
anonymous
  • anonymous
Look, do you know the value of cos(pi/6)... it's a standard value. You need to learn it. http://mathmistakes.info/facts/TrigFacts/learn/vals/sum.html << You kind of need to memorise the values only upto 90 degrees.
allank
  • allank
Hmm, I credit using the triangles approach to solving this problem, but there is an alternative and more powerful approach. Obtaining the trig values for some common angles such as pi/6, pi/4, pi/3 and their corresponding multiples can be obtained easily using a trig unit circle that I will try to sketch below.
allank
  • allank
And this is in line with @kutabs 's thinking.
Summersnow8
  • Summersnow8
ok...
Summersnow8
  • Summersnow8
so I know pi/6 is 30 degrees, now what?
allank
  • allank
|dw:1370191080199:dw| Qu
Summersnow8
  • Summersnow8
oh okay, that is awesome, but how do you get 2/sqt3
allank
  • allank
Ignore the *Qu. Site glitch. Couldn't get all the info up there, but the values along the x-axis from left to right are -1, -sqrt(3)/2, -sqrt(2)/2, 1/2, 0, 1/2, sqrt(2)/2, sqrt(3)/2,1. Exactly the same for y-axis from bottom to top. |dw:1370191981284:dw|