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Find the rate of change of f, df/dt, along the parametric curve x(t)=2t1, y(t)=32t^2 at t=1.
 10 months ago
 10 months ago
Find the rate of change of f, df/dt, along the parametric curve x(t)=2t1, y(t)=32t^2 at t=1.
 10 months ago
 10 months ago

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AlchemistaBest ResponseYou've already chosen the best response.0
We have \(f(t)=(2t−1,3−2t^2)\) then \(Df(t)=(Df_1(t),Df_2(t))=(2,−4t)\) So now we evaluate it at \(t=1\) and we have $$Df(1)=(2,−4(1))=(2,−4)$$
 10 months ago

IdealistBest ResponseYou've already chosen the best response.0
But the answer should be 8.
 10 months ago

AlchemistaBest ResponseYou've already chosen the best response.0
Are they asking for the slope of the tangent at \(t=1\)?
 10 months ago
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