anonymous
  • anonymous
Find the rate of change of f, df/dt, along the parametric curve x(t)=2t-1, y(t)=3-2t^2 at t=1.
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  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
We have \(f(t)=(2t−1,3−2t^2)\) then \(Df(t)=(Df_1(t),Df_2(t))=(2,−4t)\) So now we evaluate it at \(t=1\) and we have $$Df(1)=(2,−4(1))=(2,−4)$$
anonymous
  • anonymous
But the answer should be -8.
anonymous
  • anonymous
Are they asking for the slope of the tangent at \(t=1\)?

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