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Idealist

  • 2 years ago

Find the rate of change of f, df/dt, along the parametric curve x(t)=2t-1, y(t)=3-2t^2 at t=1.

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  1. Alchemista
    • 2 years ago
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    We have \(f(t)=(2t−1,3−2t^2)\) then \(Df(t)=(Df_1(t),Df_2(t))=(2,−4t)\) So now we evaluate it at \(t=1\) and we have $$Df(1)=(2,−4(1))=(2,−4)$$

  2. Idealist
    • 2 years ago
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    But the answer should be -8.

  3. Alchemista
    • 2 years ago
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    Are they asking for the slope of the tangent at \(t=1\)?

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