anonymous
  • anonymous
You're driving down the highway late one night at 17 when a deer steps onto the road 45 in front of you. Your reaction time before stepping on the brakes is 0.50 , and the maximum deceleration of your car is 11. How much distance is between you and the deer when you come to a stop? What is the maximum speed you could have and still not hit the deer?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
do you have answer for it?
anonymous
  • anonymous
For the distance between you and the deer I got 23m. But for the second part I have none.
anonymous
  • anonymous
do you know how to do you first part

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anonymous
  • anonymous
sorry i meant to type do you know how to do the first part*
anonymous
  • anonymous
yeah i t took me a while but i got it.
anonymous
  • anonymous
for the second one you use this equation d=vit-vi^2/2a
anonymous
  • anonymous
\[d=vit-\frac{ vi ^{2} }{ 2a}\]
anonymous
  • anonymous
rearrange into the form \[Vi ^{2}+2ad-2aVit\] solve for vi using the quatratic equation
anonymous
  • anonymous
forgot one more thing you need to plug known values then solve for vi
anonymous
  • anonymous
thanks. also for distance, should i factor in the reaction time or leave it as it is
anonymous
  • anonymous
can you show me the equation
anonymous
  • anonymous
for the reaction time?
anonymous
  • anonymous
yea
anonymous
  • anonymous
for the reaction time d = speed x time d = 17 x 0.5= 8.5 m so 45 - 8.5m =36.5 i think this is what i did
anonymous
  • anonymous
yea thats right
anonymous
  • anonymous
so i should use this distance?
anonymous
  • anonymous
that is the distance he traveled before the hits the brakes
anonymous
  • anonymous
find the distance he travels while braking and use that and subtract from 36.5
anonymous
  • anonymous
thanks :)

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