anonymous
  • anonymous
#1: Here is the overall reaction of a mercury oxide dry cell: Zn + HgO --> ZnO + Hg. In this reaction, which of the following gets oxidized? A. Hg B. O C. Zn D. HgO **not too sure.. i think it's either A or C.. what do u think @thomaster :)
Chemistry
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
#2: In which of the following combinations would you need an electroplating apparatus to coat the first metal onto the second metal? **see table attached!** A. aluminum onto lead (Pb) B. cadmium onto nickel C. tin (Sn) onto copper D. nickel onto iron **my answer; D is that right? :)
anonymous
  • anonymous
#3: In an electroplating apparatus, where does the oxidation reaction occur? A. on the surface of the cathode B. on the surface of the anode C. in the solution D. on the surface of the battery ***my answer; B not 100% sure though.. what do u think? is that right? :)
anonymous
  • anonymous
#4: Of the metals K, Fe, H, and Mg, which will spontaneously donate electrons to sodium (Na)? ***see table attached!! btw, they're the same tables haha just attached again to make it easier to see :) *** A. K B. Fe C. H D. Mg **my answer: B. Fe not too sure tho.. what do u think? :)

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thomaster
  • thomaster
#1 \(Hg^{2+} + 2e^- \rightarrow + Hg\) \(Zn \rightarrow Zn^{ 2+} + 2 e^-\) So mercury gets reduced
anonymous
  • anonymous
#5: Which of the following statements is true about a nickel-cadmium dry cell? A. The cathode reaction is Cd + 2OH- --> Cd(OH)2 + 2e-. B. The cathode reaction is NiO2 + H2O + 2e- --> Ni(OH)2 + 2OH-. C. The cathode reaction is Cd + NiO2 + 2H2O --> Cd(OH)2 + Ni(OH)2. D. The anode reaction is NiO2 + H2O + 2e- --> Ni(OH)2 + 2OH-. ***not too sure... i think its either B or D.. but I'm not sure whether its the cathode reaction or anode.. what do you think? :)
anonymous
  • anonymous
okay, so #1 is A. Hg then? :)
thomaster
  • thomaster
yes
anonymous
  • anonymous
okay! awesome :) what do you think of the others? :D
thomaster
  • thomaster
#2 Iron is higher than nickel in the list so D
anonymous
  • anonymous
kk :)
anonymous
  • anonymous
what do u think of #3? =)
thomaster
  • thomaster
#3 ew i made a mistake XD electrolating: reduction is at the surface of the cathode, not anode (this was #5 in your previous post) Oxidation is at the surface of the anode
anonymous
  • anonymous
so #5 on the previous one was D, surface of CATHODE ?
thomaster
  • thomaster
yes :P
anonymous
  • anonymous
okay! awesome :) so what would #3 be here? :D
anonymous
  • anonymous
would #3 be B. on the surface of the anode?? cuz its oxidation?
thomaster
  • thomaster
yea i just told you that :P
anonymous
  • anonymous
haha kk :) sorry! :D what about 4 and 5? :D
anonymous
  • anonymous
hey @abb0t :)
abb0t
  • abb0t
Too many questions thrown all at once.
anonymous
  • anonymous
oh oops... sorry!
thomaster
  • thomaster
i think #4 is hydrogen, not 100% sure tho #5 cadmium electrode is the cathode at this electrode reaction A occurs B is the anode reaction So i think A
anonymous
  • anonymous
okay.. so 5 is this? A. The cathode reaction is Cd + 2OH- --> Cd(OH)2 + 2e-. and 4 is this? C. H ?? :O
anonymous
  • anonymous
lol i totally did something completely wrong for #5 :/ oops! but i see what you mean now.. cathode it is :)
anonymous
  • anonymous
thank you :)
abb0t
  • abb0t
Based on the given chart, hydrogen would be the correct answer.
anonymous
  • anonymous
okay! thanks for confirming! :D

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