anonymous
  • anonymous
How do I divide x^8+x^4/x? I keep getting x^8+x^3 and I do not think that is right...is that right? ugh thanks in advance
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Jhannybean
  • Jhannybean
look back at the previous question you posted,i solved it there.
Jhannybean
  • Jhannybean
:\
johnweldon1993
  • johnweldon1993
the +x^3 part is right....but what do you multiply 'x' by to get x^8?

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More answers

anonymous
  • anonymous
ugh, I have this all over the place..I have no idea.
Jhannybean
  • Jhannybean
\[\large \frac{x^8+x^4}{x}\]\[\large \frac{x^8}{x} + \frac{x^4}{x}\] just solve each one separately
Jhannybean
  • Jhannybean
so for the first part you'd have \[\large x^{(8-1)} + x^{(4-1)}\]
Jhannybean
  • Jhannybean
i mean first and second* and @johnweldon1993 can continue....sorry john :|
anonymous
  • anonymous
10x?
johnweldon1993
  • johnweldon1993
no, you already did it before....go ahead and finish it @Jhannybean :)
anonymous
  • anonymous
I'm lost
Jhannybean
  • Jhannybean
I don't think you can add exponents when you're adding variables... :;\ only when multiplying.
anonymous
  • anonymous
oh damn
Jhannybean
  • Jhannybean
what would you get when you simplified \[\large x^{(8-1)} + x^{(4-1)}\] though?
anonymous
  • anonymous
x^7 + x^3
anonymous
  • anonymous
that is not what I get but, I think that;s it
Jhannybean
  • Jhannybean
okay, it can go a little further
Jhannybean
  • Jhannybean
See how you have a common base variable "x" ?
Jhannybean
  • Jhannybean
even though the two adding have DIFFERENT powers,we can FACTOR out a GFC, which in this case is x^3 :)
anonymous
  • anonymous
you guys rock! thanks
Jhannybean
  • Jhannybean
so you would have \[\large x^3(x^4+1)\]
anonymous
  • anonymous
I have not had math like this in like 20 years - still a work in prgress
Jhannybean
  • Jhannybean
Ohh haha yeah it happens. always have to keep practicing!
anonymous
  • anonymous
apparently...thanks again :)
Jhannybean
  • Jhannybean
noo problem!

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