anonymous
  • anonymous
Find value of x in the rhombus.
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1370228652920:dw|
anonymous
  • anonymous
I am assuming that the two polynomials you put up there are referring to the two opposite angles. As in a rhombus the opposite angles are the same, we can just set them equal to each other.\[3x^{2} - 28= 2x^{2} - 3x \] Moving all the terms to one side we get: \[x^{2} + 3x - 28= 0 \] Which can be simplified down to \[(x-4)(x+7)=0\] So x = 4 or -7. However, an angle cannot be negative here, so only the x=4 is a valid answer.
anonymous
  • anonymous
but 4 was negative, why did you change it to positive?

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anonymous
  • anonymous
Oh we are looking for a value of x that satisfies the equation (x−4)(x+7)=0 Therefore, either x-4 or x+7 must be equal to 0. And that means that x=4 or x=-7.
anonymous
  • anonymous
thank you!!
anonymous
  • anonymous
No problem!
anonymous
  • anonymous
thank you!!

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