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Solve the equation. Check your solution. 4= √h-6 A. 10 B. 100 C. √10 D. 5

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I got A is right

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Other answers:

check it; is \(4= \sqrt{10}-6\) ? \[10=\sqrt{10}\] no.
\[4= \sqrt{h}-6\\4+6= \sqrt{h}\\10=\sqrt{h}\\10^2=h \]
ok so its d
check \[4= √5-6\\10=\sqrt5? \] no
I dont get it
lets start for the start. \[4=\sqrt{h}-6\] add six to both sides \[4+6=\sqrt{h}-6+6\] tell me what you get when simplifying this
idk this is awful c right
\[4+6=\sqrt{h}-6+6\] simplify the term in the brackets \[(4+6)=\sqrt{h}+(-6+6)\]
O ok 100
what do you get when you simplify (4+6)?
right, what about (-6+6) ?
GOOD so you have \[10=\sqrt{h}\] Now square both sides \[10^2=\sqrt{h}^2\] simplify this
yes the left hand side = 100, what about the right hand side?
\[\sqrt h^2=h\]
so you have arrived at \[100=h\] now lets check. \[4= \sqrt{100}-6\] \[4=\sqrt{10^2}-6\\4=10-6\]
o ok that was confusing me....
so its B
yes, because 4=4 is always true
thanks so much!!

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