Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

|dw:1370237549168:dw|

|dw:1370237614254:dw|

I got A is right

check it;
is
\(4= \sqrt{10}-6\) ?
\[10=\sqrt{10}\]
no.

\[4= \sqrt{h}-6\\4+6= \sqrt{h}\\10=\sqrt{h}\\10^2=h
\]

ok so its d

check
\[4= √5-6\\10=\sqrt5? \] no

c?

I dont get it

ok

...

idk this is awful c right

\[4+6=\sqrt{h}-6+6\]
simplify the term in the brackets
\[(4+6)=\sqrt{h}+(-6+6)\]

O ok 100

what do you get when you simplify (4+6)?

10

right, what about (-6+6) ?

GOOD
so you have
\[10=\sqrt{h}\]
Now
square both sides
\[10^2=\sqrt{h}^2\]
simplify this

100

yes the left hand side = 100, what about the right hand side?

same

\[\sqrt h^2=h\]

so you have arrived at \[100=h\]
now lets check.
\[4= \sqrt{100}-6\]
\[4=\sqrt{10^2}-6\\4=10-6\]

o ok that was confusing me....

so its B

yes,
because 4=4 is always true

thanks so much!!