anonymous
  • anonymous
Multiply and simplify Radical Expression 1/2√5(1 1/2√20)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1370239174862:dw|
anonymous
  • anonymous
Hi I got the answer of 7/2√5 but when I do it I get something different.
anonymous
  • anonymous
okay so lets write that a little prettier to deal with:\[{{1\over2}\sqrt{5}}\times{1~{1\over2}\sqrt{20}}~~\implies~~{{1\over2}\sqrt{5}}\times{{3\over2}\sqrt{20}}~~\implies~~{\sqrt{5}\over2}\times{3\sqrt{20}\over2}\]now that that looks a little better, let's solve:\[{{\sqrt{5}\times3\sqrt{20}}\over2}={3\sqrt{100}\over2}\]because 5 x 20 = 100\[3(10)\over2\]i think you've got it from here :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
oh i meant to write \[3(10)\over4\]sorry
anonymous
  • anonymous
I'm a bit lost I have to simplify this so would'nt 1 1/2√20 be 2 3/2√5
anonymous
  • anonymous
\[1 {1\over2} = {3\over2}\]\[\sqrt{20}= 2\sqrt{5}\]\[{3\over2}\times{2\over1}\sqrt{5}~~=~~{3\over\cancel{2}}\times{\cancel{2}\over1}\sqrt{5}~~=~~\large3\sqrt{5}\]
anonymous
  • anonymous
but the answer comes out to \[\frac{ 7 }{ 2 }\sqrt{5}\]
anonymous
  • anonymous
and where are you getting this from?
anonymous
  • anonymous
Our teacher placed the answer as \[\frac{ 7 }{ 2 }\sqrt{5}\]
anonymous
  • anonymous
I didn't get this answer either this is why it's confusing
anonymous
  • anonymous
1/2 times 3/2 = 3/4 sqrt 5 times sqrt 20 = sqrt100 = 10 3/4 times 10 = 7.5 i dont know what your teacher was doing, maybe you copied the question wrong
anonymous
  • anonymous
No it's printed on my paper
anonymous
  • anonymous
then im really not sure
anonymous
  • anonymous
I appreciate your help Thank you yummydum
anonymous
  • anonymous
no problem :)
anonymous
  • anonymous
I got as my final answer \[\frac{ 3 }{ 4 }\sqrt{5} \] this is why it was confusing
anonymous
  • anonymous
I had a person help me don't I don't believe it's correct here is why unless I'm wrong
saifoo.khan
  • saifoo.khan
Alright so i read the whole problem. Where are you stuck? We should get 15/2.
anonymous
  • anonymous
\[1\frac{ 1 }{ 2 }\sqrt{20}\] would be \[\frac{ 3 }{ 2 }\] and \[\sqrt{20} would be 2\] add both \[2\frac{ 3 }{ 2 }\sqrt{5}\]
anonymous
  • anonymous
teacher has an answer of \[\frac{ 7 }{ 2 }\sqrt{5}\] could the teacher be wrong
saifoo.khan
  • saifoo.khan
Yes. Teacher added the sqrt5 by misatke. Or maybe the question you wrote is incorrect.
anonymous
  • anonymous
question is multiply and simplify \[\frac{ 1 }{ 2 }\sqrt{5}\left( 1\frac{ 1 }{ 2 } \sqrt{20}\right)\]
saifoo.khan
  • saifoo.khan
|dw:1370243682678:dw|
anonymous
  • anonymous
Why is this so complicated? I'm lost
saifoo.khan
  • saifoo.khan
Which step is it that you don't understand?
anonymous
  • anonymous
how would I multiply \[\frac{ \sqrt{5} }{ 2 }\times \frac{ 3*2 }{ 2 }\sqrt{5}\] I thought you multiply numbers not square roots with numbers
anonymous
  • anonymous
my answer was \[\frac{ 3 }{ 4 }\sqrt{5}\] maybe this is wrong
saifoo.khan
  • saifoo.khan
|dw:1370244388921:dw|
anonymous
  • anonymous
Wouldn't we keep the root? and just multiply getting \[\frac{ 15 }{ 2 }\sqrt{5}\]
saifoo.khan
  • saifoo.khan
No ma'am. Whenever it's given: sqrt3 * sqrt3 we will get "3" as answer. The roots cancel out leaving you with ONE three.
anonymous
  • anonymous
This is how I started \[\frac{ 1 }{ 2 }\sqrt{5}(1\frac{1 }{ 2 }\sqrt{20})\] \[\frac{ 1 }{ 2 }\sqrt{5}(\frac{3 }{ 2 }\sqrt{5})\] \[\frac{ 1 }{ 2 }\times \frac{ 3 }{ 2 }=\frac{ 3 }{ 4 }\sqrt{5}\] I know this isn't corrected but I get this
saifoo.khan
  • saifoo.khan
How will you simplify sqrt 20?
anonymous
  • anonymous
that's right it would be 4*5 which 4 goes down to 2 so it would be \[2\sqrt{5}\]
saifoo.khan
  • saifoo.khan
^
anonymous
  • anonymous
I forgot to add that \[\frac{ 1 }{ 2 }\sqrt{5}(2\frac{3 }{ 2 }\sqrt{5})\] it would be this correct and mix fractions to improper fractions would be \[2\frac{ 3 }{ 2 } would be \frac{ 7 }{ 2 }\] \[\frac{ 1 }{ 2 }\sqrt{5}(\frac{ 7 }{ 2 }\sqrt{5})\]
saifoo.khan
  • saifoo.khan
You made a mistake again. :P It's not 2 3/2
anonymous
  • anonymous
so it's \[\frac{ 2 }{ 1 }X\frac{ 3 }{ 2 }\]
saifoo.khan
  • saifoo.khan
No. I think you should redo the problem. Show me yor steps please.
anonymous
  • anonymous
ok
anonymous
  • anonymous
\[\frac{ 1 }{ 2 }\sqrt{5}(1\frac{ 1 }{ 2 }\sqrt{20})\] \[\frac{ 1 }{ 2 }\sqrt{5}(\frac{ 3 }{ 2 } 2\sqrt{5})\] \[\frac{ 1 }{ 2 }\sqrt{5}(\frac{ 3 }{ 2 } 2\sqrt{5})\] at this point I'm lost
saifoo.khan
  • saifoo.khan
Awesome. No the 2's on right cancels out. Right?
anonymous
  • anonymous
why would it cancel √20 would be 2√5 this is where I'm getting confused
anonymous
  • anonymous
is 2 canceling with the other 2
saifoo.khan
  • saifoo.khan
sqrt(20) = sqrt(2*2*5) = 2 sqrt5 Agree?
anonymous
  • anonymous
yes
saifoo.khan
  • saifoo.khan
Now the 2 from 2sqrt5 and the w in the denominator on the right canel out
anonymous
  • anonymous
I'm with you on that
saifoo.khan
  • saifoo.khan
Right o what are we left with now?
anonymous
  • anonymous
3√5
saifoo.khan
  • saifoo.khan
Right. And that is multiplied with..?
anonymous
  • anonymous
\[\frac{ 1 }{ 2 }\sqrt{5}\]
saifoo.khan
  • saifoo.khan
Right now multiply it out.
anonymous
  • anonymous
\[\frac{ 1 }{ 2 }\sqrt{5}\times \frac{ 3 }{ 1 }\sqrt{5}\] Is this looking correct?
saifoo.khan
  • saifoo.khan
yes
anonymous
  • anonymous
\[\frac{ 3 }{ 2 }\sqrt{5}\]
anonymous
  • anonymous
do I take of the √ and make it \[\frac{ 3 }{ 2 }\times \frac{ 5 }{ 1 }=\frac{ 15 }{ 2 }\]
saifoo.khan
  • saifoo.khan
Like a boss. (y)
anonymous
  • anonymous
Thanks for everything wow :.)
anonymous
  • anonymous
Good job helping @newatthis !!! @saifoo.khan
anonymous
  • anonymous
Kudos to @yummydum too!
saifoo.khan
  • saifoo.khan
@yummydum is useless.
anonymous
  • anonymous
No she isn't :p
anonymous
  • anonymous
I'M useless.
anonymous
  • anonymous
Yummydum isn't. Or you,for that matter.
anonymous
  • anonymous
Thanks for everything it helps a lot when someone knows how to guide and explain it. :)
saifoo.khan
  • saifoo.khan
@help123please. believe me. I know her. @newatthis You're welcome. :)
anonymous
  • anonymous
Well,yes...you've been here longer than me.
saifoo.khan
  • saifoo.khan
Lol. But no doubt she has a brown brain like me! D:
anonymous
  • anonymous
O_O
anonymous
  • anonymous
Yours is a great brain,Saif.
anonymous
  • anonymous
U ARE 2 HELPFUL. Lol.
saifoo.khan
  • saifoo.khan
And it's brown too!
anonymous
  • anonymous
Nope it's not.
saifoo.khan
  • saifoo.khan
I'm brown. Brain is brown too. Dummy is brown too. Hence she has a brown brain too.
anonymous
  • anonymous
We're prolly weirding @newatthis out. Or at least,I am.
anonymous
  • anonymous
:P
anonymous
  • anonymous
'Hence,she has a brown brain too'. Hence. I like that word.
saifoo.khan
  • saifoo.khan
Lol.
anonymous
  • anonymous
no I'm just doing math working my brain, or whatever is left. :)
anonymous
  • anonymous
Saif,I just noticed your smartscore is mine,with the numbers flipped upside down. XD
saifoo.khan
  • saifoo.khan
Haha. Nice catch.
anonymous
  • anonymous
IKR.
anonymous
  • anonymous
*Flips PC upside down* OMGEE I HAVE A 99 SS!
saifoo.khan
  • saifoo.khan
Lol.
anonymous
  • anonymous
98% of the time,when typing lol,you're not actually laughing. Did u know? :P
saifoo.khan
  • saifoo.khan
Make that 99%. I love laughing. It helps in exercising my face muscles. :P
anonymous
  • anonymous
Lawl.
saifoo.khan
  • saifoo.khan
;)
anonymous
  • anonymous
so new question? \[2x \sqrt{7}(3x \sqrt{7})\] \[2x(3x)\sqrt{7}\sqrt{7}\] \[6x(\sqrt{49})\] Would this be correct?
anonymous
  • anonymous
sorry I just threw this in here
anonymous
  • anonymous
@newatthis please close this post and create a new thread.
anonymous
  • anonymous
2x * 3x = 6x^2 not just 6x and √49 = 7 so now you have 6x^2 * 7 ....which is?
anonymous
  • anonymous
\[42x ^{2}\]
anonymous
  • anonymous
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.