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Tabbiejack

  • 2 years ago

Simplify the expression. √6(√33+7) A. √39+7√6 B. √198+7 C. 3√22+7√6 D. √198+7√6

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  1. Tabbiejack
    • 2 years ago
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    @experimentX please help

  2. Tabbiejack
    • 2 years ago
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    I got C

  3. Jhannybean
    • 2 years ago
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    oh my goodness.bad mistake.

  4. Jhannybean
    • 2 years ago
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    it's not sqrt{37} it's sqrt{33} -_-

  5. Tabbiejack
    • 2 years ago
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    so the answer is not c then

  6. Jhannybean
    • 2 years ago
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    \[\large \sqrt{6}(\sqrt{33}+7)\]\[\large \sqrt{a}*\sqrt{b} \implies \sqrt{6}*\sqrt{33}=\sqrt{198}\]\[\large \sqrt{6}*7 \implies 7\sqrt{6}\]altogether \[\large \sqrt{6}(\sqrt{33}+7)= \sqrt{198}+7\sqrt{6}\]

  7. Tabbiejack
    • 2 years ago
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    o ok thanks so much

  8. Jhannybean
    • 2 years ago
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    Sorry about that... i wrote \(\sqrt{37} \) instead of \(\sqrt{33}\)

  9. Tabbiejack
    • 2 years ago
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    so you saying it was D and that is not write

  10. Tabbiejack
    • 2 years ago
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    right sorry

  11. Tabbiejack
    • 2 years ago
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    it came up wrong

  12. Jhannybean
    • 2 years ago
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    it came up wrong? how come?

  13. saifoo.khan
    • 2 years ago
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    OMG! Jaan baji made a mistake!! =D

  14. Eyad
    • 2 years ago
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    \[\Huge \color{Red}{\bf \bigstar}\]

  15. Jhannybean
    • 2 years ago
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    You are right @Tabbiejack .\[\large \sqrt{198} = \sqrt{18*11} = \sqrt{9*2*11} = \sqrt{3*3*2*11} = 3\sqrt{22}\] So this would be \[\large 3 \sqrt{22}+7\sqrt{6}\] goodjob.

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