Tabbiejack
Simplify the expression.
√6(√33+7)
A. √39+7√6
B. √198+7
C. 3√22+7√6
D. √198+7√6
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Tabbiejack
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@experimentX please help
Tabbiejack
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I got C
Jhannybean
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oh my goodness.bad mistake.
Jhannybean
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it's not sqrt{37} it's sqrt{33} -_-
Tabbiejack
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so the answer is not c then
Jhannybean
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\[\large \sqrt{6}(\sqrt{33}+7)\]\[\large \sqrt{a}*\sqrt{b} \implies \sqrt{6}*\sqrt{33}=\sqrt{198}\]\[\large \sqrt{6}*7 \implies 7\sqrt{6}\]altogether \[\large \sqrt{6}(\sqrt{33}+7)= \sqrt{198}+7\sqrt{6}\]
Tabbiejack
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o ok thanks so much
Jhannybean
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Sorry about that... i wrote \(\sqrt{37} \) instead of \(\sqrt{33}\)
Tabbiejack
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so you saying it was D and that is not write
Tabbiejack
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right sorry
Tabbiejack
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it came up wrong
Jhannybean
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it came up wrong? how come?
saifoo.khan
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OMG! Jaan baji made a mistake!! =D
Eyad
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\[\Huge \color{Red}{\bf \bigstar}\]
Jhannybean
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You are right @Tabbiejack .\[\large \sqrt{198} = \sqrt{18*11} = \sqrt{9*2*11} = \sqrt{3*3*2*11} = 3\sqrt{22}\] So this would be \[\large 3 \sqrt{22}+7\sqrt{6}\] goodjob.