anonymous
  • anonymous
Simplify the expression. √6(√33+7) A. √39+7√6 B. √198+7 C. 3√22+7√6 D. √198+7√6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@experimentX please help
anonymous
  • anonymous
I got C
Jhannybean
  • Jhannybean
oh my goodness.bad mistake.

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More answers

Jhannybean
  • Jhannybean
it's not sqrt{37} it's sqrt{33} -_-
anonymous
  • anonymous
so the answer is not c then
Jhannybean
  • Jhannybean
\[\large \sqrt{6}(\sqrt{33}+7)\]\[\large \sqrt{a}*\sqrt{b} \implies \sqrt{6}*\sqrt{33}=\sqrt{198}\]\[\large \sqrt{6}*7 \implies 7\sqrt{6}\]altogether \[\large \sqrt{6}(\sqrt{33}+7)= \sqrt{198}+7\sqrt{6}\]
anonymous
  • anonymous
o ok thanks so much
Jhannybean
  • Jhannybean
Sorry about that... i wrote \(\sqrt{37} \) instead of \(\sqrt{33}\)
anonymous
  • anonymous
so you saying it was D and that is not write
anonymous
  • anonymous
right sorry
anonymous
  • anonymous
it came up wrong
Jhannybean
  • Jhannybean
it came up wrong? how come?
saifoo.khan
  • saifoo.khan
OMG! Jaan baji made a mistake!! =D
anonymous
  • anonymous
\[\Huge \color{Red}{\bf \bigstar}\]
Jhannybean
  • Jhannybean
You are right @Tabbiejack .\[\large \sqrt{198} = \sqrt{18*11} = \sqrt{9*2*11} = \sqrt{3*3*2*11} = 3\sqrt{22}\] So this would be \[\large 3 \sqrt{22}+7\sqrt{6}\] goodjob.

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