Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

help123please. Group TitleBest ResponseYou've already chosen the best response.1
@saifoo.khan
 one year ago

newatthis Group TitleBest ResponseYou've already chosen the best response.0
\[2x(3x)\sqrt{7}\sqrt{7}\]
 one year ago

newatthis Group TitleBest ResponseYou've already chosen the best response.0
\[6x \sqrt{49}\]
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.3
6x^2 rest is right.
 one year ago

newatthis Group TitleBest ResponseYou've already chosen the best response.0
\[6x ^{2}\sqrt{49}\]
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.3
simplify the root.
 one year ago

newatthis Group TitleBest ResponseYou've already chosen the best response.0
it would be 7
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.3
Indeed.
 one year ago

newatthis Group TitleBest ResponseYou've already chosen the best response.0
so I can't multiply them right it's not like terms \[6x ^{2} \] and 7
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.3
But you can multiply 6and 7. Making it something.
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.3
I gtg guys. See ya awl later.
 one year ago

newatthis Group TitleBest ResponseYou've already chosen the best response.0
\[42x ^{2}\]
 one year ago

newatthis Group TitleBest ResponseYou've already chosen the best response.0
Thanks @saifoo.khan
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.