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newatthis

2x√7(3x√7)

  • 10 months ago
  • 10 months ago

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  1. help123please.
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    @saifoo.khan

    • 10 months ago
  2. newatthis
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    \[2x(3x)\sqrt{7}\sqrt{7}\]

    • 10 months ago
  3. newatthis
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    \[6x \sqrt{49}\]

    • 10 months ago
  4. saifoo.khan
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    6x^2 rest is right.

    • 10 months ago
  5. newatthis
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    \[6x ^{2}\sqrt{49}\]

    • 10 months ago
  6. saifoo.khan
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    simplify the root.

    • 10 months ago
  7. newatthis
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    it would be 7

    • 10 months ago
  8. saifoo.khan
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    Indeed.

    • 10 months ago
  9. newatthis
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    lol :)

    • 10 months ago
  10. newatthis
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    so I can't multiply them right it's not like terms \[6x ^{2} \] and 7

    • 10 months ago
  11. saifoo.khan
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    But you can multiply 6and 7. Making it something.

    • 10 months ago
  12. saifoo.khan
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    I gtg guys. See ya awl later.

    • 10 months ago
  13. newatthis
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    \[42x ^{2}\]

    • 10 months ago
  14. newatthis
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    Thanks @saifoo.khan

    • 10 months ago
  15. saifoo.khan
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    • 10 months ago
  16. newatthis
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    nice :)

    • 10 months ago
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