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help123please.
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@saifoo.khan

newatthis
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\[2x(3x)\sqrt{7}\sqrt{7}\]

newatthis
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\[6x \sqrt{49}\]

saifoo.khan
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6x^2
rest is right.

newatthis
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\[6x ^{2}\sqrt{49}\]

saifoo.khan
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simplify the root.

newatthis
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it would be 7

saifoo.khan
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Indeed.

newatthis
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lol :)

newatthis
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so I can't multiply them right it's not like terms \[6x ^{2} \] and 7

saifoo.khan
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But you can multiply 6and 7. Making it something.

saifoo.khan
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I gtg guys. See ya awl later.

newatthis
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\[42x ^{2}\]

newatthis
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Thanks @saifoo.khan

saifoo.khan
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newatthis
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nice :)