anonymous
  • anonymous
without using calculator,find all the angles in between 0' and 360' which satisfy the following trigonometric equation. sin3x=cos(90'-2x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
use the difference identity on cos (90-2x)
anonymous
  • anonymous
difference identity?
anonymous
  • anonymous
yeah, there's an identity for simplifying cos (a-b) to something else but i'm too lazy to look it up today

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anonymous
  • anonymous
and for the sin 3x http://library.thinkquest.org/17119/media/3_211.gif
anonymous
  • anonymous
is it like that? 3sinx-4sin^3 x= cos90cos2x+sin90sin2x 3sinx-4sin^3 x=sin2x 3sinx-4sin^3 x -sin 2x=0
anonymous
  • anonymous
now use the double angle identity for sin 2x

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