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Assume an \(8\times 8\) chessboard with usual colouring. You may repaint all the squares of a row or column. The goal is to attain one black square. Possible?

Mathematics
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yes
i think
do u need explanation

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Other answers:

What does repaint mean? Invert the colours of a row? (IE turn all light squares dark and vice versa)
ok suppose that we want one black square that is how we can do it
black square is in the middle lets say at 4rth row and 4rth coloumn
yes
first we paint all the rows except 4rth one with white color not 4rth row 4rth row must have one black
then we paint all coloumns with white except 4rth coloumn
So, in simple terms, repainting is a function that maps... |dw:1370257845631:dw|
in this way all the remaining except the the one we said will be white and only one which is at location 4rth row and 4rth coloumn would be white
so ans is yes
ok repainting means painting what you want to paint if 1 row is to be repainted with white then all the squares in that row would be white
I guess so @terenzreignz , because the answer at back is 'no'.
Well then, \[\large \left[\begin{matrix}0&1&0&1&0&1&0&1 \\1&0&1&0&1&0&1&0\\0&1&0&1&0&1&0&1\\1&0&1&0&1&0&1&0\\0&1&0&1&0&1&0&1\\1&0&1&0&1&0&1&0\\0&1&0&1&0&1&0&1\\1&0&1&0&1&0&1&0\end{matrix}\right]\] Okay, let's start with this... 0 = light square 1 = dark square
Let's repaint the 1st, 3rd, 5th and 7th rows (starting from the top) 1&0&1&0&1&0&1&0 \[\large \left[\begin{matrix}1&0&1&0&1&0&1&0\\1&0&1&0&1&0&1&0\\1&0&1&0&1&0&1&0\\1&0&1&0&1&0&1&0\\1&0&1&0&1&0&1&0\\1&0&1&0&1&0&1&0\\1&0&1&0&1&0&1&0\\1&0&1&0&1&0&1&0\end{matrix}\right]\]
Okay, nvm, I lost myself :D
It might the case that no matter how you repaint, you always add/subtract an even number of dark squares.... so you can't end up with just 1...
Though you could always repaint the second, fourth, sixth, and eight columns (from the left) and end up with one (really big) dark square XD
That's it.

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