anonymous
  • anonymous
A region bounded by f(x) = sqrt(x + 4) , y = 1, and x = 0 is shown below. Find the volume of the solid formed by revolving the region about the x-axis.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
\[V=\pi\int_{-3}^0\left[\left(\sqrt{x+4}\right)^2-(1)^2\right]~dx\]
anonymous
  • anonymous
okay so i integrate that?

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anonymous
  • anonymous
i get 34.87 what do i do next?
anonymous
  • anonymous
@Luigi0210
Luigi0210
  • Luigi0210
Luigi0210 is not here.. please leave a message after the beep.. *beep* Ha I'm just messing.. but I think that's set up correctly. @Loser66
anonymous
  • anonymous
lol okay i solved and i got that so what do i do next?
anonymous
  • anonymous
i got 6pi for the final answer ? :/
Luigi0210
  • Luigi0210
@dan815 I might not be good at volume but I'm great at calling for help ^_^'
anonymous
  • anonymous
hahaha okay
Luigi0210
  • Luigi0210
@Jhannybean
Luigi0210
  • Luigi0210
@ajprincess
ajprincess
  • ajprincess
I am really sorry @onegirl and @Luigi0210. i too havnt any idea
Luigi0210
  • Luigi0210
D: well thanks for coming and trying ^_^'
Luigi0210
  • Luigi0210
and I kind of tried the problem and I got (9/2)pi.. which is probably a 99.99% wrong
anonymous
  • anonymous
hmmm 9/2pi is in one of my multiple choices soo
Luigi0210
  • Luigi0210
you probably shouldn't take my word for it.. I have a tendency of getting volume problems wrong :/
anonymous
  • anonymous
okay
Luigi0210
  • Luigi0210
what are your other possible choices?
Loser66
  • Loser66
show me your work, @Luigi0210
Loser66
  • Loser66
I think SithsAng....gave out the right equation
Loser66
  • Loser66
=20pi
anonymous
  • anonymous
there is 6pi, 5pi and 4pi
Luigi0210
  • Luigi0210
\[\Pi \int\limits_{-3}^{0}[(x-4)-(1)]dx\] \[\Pi [\frac{ x^2 }{ 2 }+4x-(x)]\] \[\Pi [0-(\frac{ 9 }{ 2 }-12+3)]\] \[\Pi[0-(\frac{ 9 }{ 2 }-9)]\] \[\Pi[0-(\frac{ 9 }{ 2 })\] \[\frac{ 9 }{ 2 } \Pi\]
anonymous
  • anonymous
but 20pi isn't in my choices..
Luigi0210
  • Luigi0210
there's suppose to be a negative on the 9/2.. second last :/
anonymous
  • anonymous
okay
Luigi0210
  • Luigi0210
sorry if it's wrong :/
anonymous
  • anonymous
its okay
Loser66
  • Loser66
why (x+4 ) not x -4 and then (x+4) -1 =x+3 and then take integral
Loser66
  • Loser66
|dw:1370280130430:dw|
Loser66
  • Loser66
|dw:1370280238253:dw|
Luigi0210
  • Luigi0210
>.<
Loser66
  • Loser66
am I wrong? hehehe.... not good at calculation.hopefully there is no mistake there
Loser66
  • Loser66
@Luigi0210 what do you mean by this symbol? please, verbalize your message
Loser66
  • Loser66
@Luigi0210 you see. I am too old , cannot understand your teen language or symbol
anonymous
  • anonymous
lol ok
Loser66
  • Loser66
@onegirl @Luigi0210 knock, knock.. where are you?? the net is not good here, if you guys don't reply, I go and it takes long time to get back.
Luigi0210
  • Luigi0210
I should throw in the towel :l
anonymous
  • anonymous
okay i see what you did
Luigi0210
  • Luigi0210
Throw in the towel? as in quit? :/

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