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Not sure what, "What is the image of A described by the vector(-4,-6)?" is even asking. As for the translation, do you know what his means? What could you multiply the vector by to get to a different destination?
@e.mccormick I'm not sure :/ I'm not good at this stuff
First, are these just points in space? Just want to be clear on what these are. Why is simple. If they are points, then the translation vector is a vector that would take the first point and land it at the second point. On the other hand, if these are terminal points for vectors, it is a little different.
I'm not really sure what they'd be? We didn't learn about that.
But you were just given an image with dots? If so, then the translation vector is just what would take B's values and move them to D's.
I don't know :( honestly I'm about to just put something random down because I don't understand at all
In this type of vector, the top value is the chaneg in x and the bottom is the change in y.
Would it be -8,-8
Yes, \((-8,-8)\) translates B to D. And that first question seems to be asking where would the dot be if you did the translation \((-4,-6)\) to it. Just never seen it worded quite that way.
I think that's what it means to but I'm not sure what that one would be
Well, you took B, did -8, -8 and got -2, -2. If you take A, (2,4) and add (-4,-6) you get what? And yes, the end point will be familliar...
Wait now I am confused... Is my answer for the 2nd question -8,-8 or -2,-2?!
The first is (-8, -8), the second is (-2,-2).... Just pointing out that for whatever reason they seem to have both translating to D.
Aak... reverse that... we did he queastions in reverse order.
Ok so the first question or the image of A is -2,-2 and then second question is -8,-8
So the first is (-2,-2) or it lands on D. The second (which we did first), is (-8,-8).
Yah, I am pretty sure hat is what they want for the first question. The second, yah, that is how they work. Here is a reference to things like the second question: http://www.cimt.plymouth.ac.uk/projects/mepres/book9/bk9i7/bk9_7i2.html