anonymous
  • anonymous
Calculus - help with part b only [see attachment]
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
I know d/t = v takes place to help find the answer. The faster B is the farther from a until a certain point.
anonymous
  • anonymous
As long as car B drives faster than car A the distance between them will _increase_. At t = 2.5 the distance between them is constant and then as the speed of car A becomes faster than that of car B the distance will _decrease_.

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anonymous
  • anonymous
so would the answer be at 2.5 when it is the greatest?
Jhannybean
  • Jhannybean
I think it's a little more than 2.5.
dumbcow
  • dumbcow
\[Distance = \int\limits_{0}^{t}(V_B -V_A) dt\] to maximize distance, set derivative equal to 0 \[\frac{d}{dt} \int\limits\limits_{0}^{t}(V_B -V_A) dt = 0\] \[V_B -V_A = 0\] \[V_B = V_A\] so max distance occurs at time when Car A velocity catches up to car B velocity
anonymous
  • anonymous
thank you.

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