DDCamp
  • DDCamp
One map has a scale of 3/4 inches to a mile, and another a scale of 5/8 of an inch to a mile. If the sum of the lengths between two cities on the maps is 55 inches, how far apart are they in real life?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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DDCamp
  • DDCamp
Is this how it works? |dw:1370297527581:dw|
jdoe0001
  • jdoe0001
yes DDCamp , more or less
jdoe0001
  • jdoe0001
x = actual distace small map says is really (3/4)x bigger map says is really (5/8)x add them up together and those 2 give 55 in actual distance, so $$ \cfrac{3}{4}x+\cfrac{5}{8}x=55 \implies x\pmatrix{\cfrac{3}{4}+\cfrac{5}{8}}\\ \implies x\pmatrix{\cfrac{11}{8}} = 55 $$ solve for "x", and see what you get

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DDCamp
  • DDCamp
Thanks!
jdoe0001
  • jdoe0001
anyhow, you already know the answer, is 40, yes :)
jdoe0001
  • jdoe0001
yw

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