anonymous
  • anonymous
Assume that lines that appear to be tangent are tangent. Point O is the center of the circle. Find the value of x. (Not drawn to scale)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
m
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anonymous
  • anonymous
A. 316 B. 272 C. 68 D. 44
anonymous
  • anonymous
Please explain how to do this problem =)

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More answers

ganeshie8
  • ganeshie8
use this :- sum of angles in a quadrilateral = 360
anonymous
  • anonymous
I don't understand :I
ganeshie8
  • ganeshie8
google and tell me what a quadrilateral is
anonymous
  • anonymous
I'm not stupid .-. A quad has 4 sides
ganeshie8
  • ganeshie8
then, use its property
ganeshie8
  • ganeshie8
you knw m
anonymous
  • anonymous
I'm a bit confused, why are we talking quads when its a circle? Can't we just say a circle is 360?
ganeshie8
  • ganeshie8
dont u see a quadrilateral there ?
anonymous
  • anonymous
Well yeah but my teacher never mentioned quads, just arcs and stuff. Sorry =/
ganeshie8
  • ganeshie8
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ganeshie8
  • ganeshie8
its okay, you need to use quadrilateral properties here
anonymous
  • anonymous
I'm used to the arcs and angles being inside the circles. But please continue =)
ganeshie8
  • ganeshie8
when you're doing circles, it is assumed that you knw very well about quadrilateral. nobody learns circles without first learning quadrilaterals
anonymous
  • anonymous
I do, I just wasn't introduced with using them both together.
ganeshie8
  • ganeshie8
okay good, wat made u think im treating u like that ha
anonymous
  • anonymous
Nevermind. How do I find the x? Would I subtract something from 360?
ganeshie8
  • ganeshie8
tell me this :- for a circle, whats the angle formed between a tangent and radius ?
anonymous
  • anonymous
Umm, I'm not quite sure what your talking about. The arc? Central angle?
anonymous
  • anonymous
inscribed angle?
ganeshie8
  • ganeshie8
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ganeshie8
  • ganeshie8
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ganeshie8
  • ganeshie8
|dw:1370301419747:dw|
ganeshie8
  • ganeshie8
that angle is the angle between radius and tangent. it wud be 90 !
anonymous
  • anonymous
Oh! Is it a chord?
ganeshie8
  • ganeshie8
chord is different, chord cuts the circle at two points, and lies inside circle.
ganeshie8
  • ganeshie8
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dumbcow
  • dumbcow
oh my goodness there is a geometry formula for this
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ganeshie8
  • ganeshie8
you knw the 3 angles in the quadrilateral, you can find the fourth ?
anonymous
  • anonymous
144?
ganeshie8
  • ganeshie8
Yes !
ganeshie8
  • ganeshie8
you can use the formula above given by dumbcow also :)
anonymous
  • anonymous
That was easier than I though 0.o. But the formula looks confusing
ganeshie8
  • ganeshie8
but this method i like cuz we dont have remember formulas..
ganeshie8
  • ganeshie8
yea its easy once we do it once :)
anonymous
  • anonymous
Thanks ganeshie!
ganeshie8
  • ganeshie8
np :)
anonymous
  • anonymous
@ganeshie8 One more thing. This one confused me because they are using side measures? not angles?
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ganeshie8
  • ganeshie8
yeah, its just pythagora.. let me draw and show u :)
anonymous
  • anonymous
Okay! Thanks!
ganeshie8
  • ganeshie8
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ganeshie8
  • ganeshie8
\(OA^2 + AB^2 = OB^2\)
ganeshie8
  • ganeshie8
\(4000^2 + 17000^2 = OB^2\)
ganeshie8
  • ganeshie8
find OB first
ganeshie8
  • ganeshie8
then subtract the radius 4000 from OB, you would get distance from earth's surface BC
anonymous
  • anonymous
Okay, I'll give it a try
ganeshie8
  • ganeshie8
okie
anonymous
  • anonymous
The squares are confusing me. would I square them then add?
ganeshie8
  • ganeshie8
yes
ganeshie8
  • ganeshie8
guess i wud factor out 1000^2 frm both
ganeshie8
  • ganeshie8
\(4000^2 + 17000^2 = OB^2 \) \(1000^2(4^2 + 17^2) = OB^2 \) \(1000^2(16 + 289) = OB^2 \)
anonymous
  • anonymous
Wow, now I'm really confused. You do math a lot different then I do
ganeshie8
  • ganeshie8
\(1000^2(305) = OB^2 \) \(1000 \sqrt{(305)} = OB \) \(17464 = OB\)
ganeshie8
  • ganeshie8
its okay !
ganeshie8
  • ganeshie8
you can simplify stuff anyway u wish
ganeshie8
  • ganeshie8
now that OB, you need to subtract the radius 4000 from above to get wat they asking in the problem.
anonymous
  • anonymous
13,464
anonymous
  • anonymous
Thanks again! Its really kind of you to take you time to teach someone =) THANK YOU!!!
ganeshie8
  • ganeshie8
np :) you're welcome :))

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