anonymous
  • anonymous
I don't know how to do this. Solve the equation. Identify any extraneous solutions. x= square root x +30
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[x=\sqrt{x+30}\] \[x^2=x+30\]\[x^2-x-30=0\] solve the quadratic
anonymous
  • anonymous
How do you solve a quadratic?
anonymous
  • anonymous
this one factors as \[(x-6)(x+5)=0\] so \(x=6\) or \(x=-5\) then check the original equation you will see that \(6\) works and \(-5\) does not

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anonymous
  • anonymous
so what is the extraneous idk what that means
anonymous
  • anonymous
it means the one that doesn't work
anonymous
  • anonymous
6 works because \[6=\sqrt{6+30}\] \[6=\sqrt{36}\]\[6=6\] is true
anonymous
  • anonymous
oh thanks
anonymous
  • anonymous
-5 does not work because \[-5\neq \sqrt{-5+30}\] \[-5\neq \sqrt{25}\] \[-5\neq 5\]
anonymous
  • anonymous
yw
anonymous
  • anonymous
oh see i didn't know that was how it works

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