From the top and bottom views, you are looking at squares. The smaller square has sides that equal 4cm, the larger square has sides that equal 6cm. Then you have 4 trapezoids with $$base_1 = 4$$ and $$base_2 = 6$$ and a height of 5. The surface area of this figure is simply the area of each of these shapes combined. The formula will look like this: $surface~area = area(top) + area(bottom) + 4(area(trapezoid))$ The area of a square is $$side^2$$ and the area of a trapezoid is $$\frac{1}{2}h(b_1+b_2)$$ $sa = 4^2 + 6^2 + 4(\frac{1}{2}(5)(4+6))$ The rest is just arithmetic: $sa = 16 + 36 + 4(\frac{1}{2}(5)(10)$ $sa = 52 + 4(\frac{1}{2}(50))$ $sa = 52 + 4(25)$ $sa = 52 + 100$ $sa = 152$