anonymous
  • anonymous
What is the equation of the line in slope-intercept form that passes through the point (1, 3) and is perpendicular to the line y = –x + 2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
do you know what the slope of \(y=-x+2\) is ?
anonymous
  • anonymous
-1?
anonymous
  • anonymous
yes

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anonymous
  • anonymous
do you know what the slope of the perpendicular line would be?
anonymous
  • anonymous
no, thats what i'm having trouble understanding. Is it -1?
anonymous
  • anonymous
no
anonymous
  • anonymous
if the slope of a line is \(m\) then the perpendicular line will have slope \(-\frac{1}{m}\) sometimes called the "negative reciprocal"
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
so for example if the slope of a line is 2, the perpendicular line will have slope \(-\frac{1}{2}\)
anonymous
  • anonymous
and if the slope of a line is \(-\frac{3}{4}\) the perpendicular line will have slope \(\frac{4}{3}\)
anonymous
  • anonymous
so would it be -1/1?
anonymous
  • anonymous
your slope is already negative, it is \(-1\) the perpendicular line will have a positive slope
anonymous
  • anonymous
so 1/1
anonymous
  • anonymous
yeah, better known as \(1\)
anonymous
  • anonymous
lol, yeah. ok, i understand, so then how do we get the y-intercept? Do we keep it from the equation? So for instance it would be y=x+2
anonymous
  • anonymous
?*
anonymous
  • anonymous
now that you have the slope is 1, and the point is \((1,3)\) use the "point - slope" formula
anonymous
  • anonymous
\[y-y_1=m(x-x_1)\] \[y-3=1(x-1)\] \[y=x+2\] yeah you have it it was silly of me to write the 1 there, just to make it clear
anonymous
  • anonymous
I just did that on my paper! Cool! I fully understand this now, thank you so much for helping me. You're really the best!
anonymous
  • anonymous
yw

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