anonymous
  • anonymous
Solve the equation \[\sqrt{2x-3}\] +5 =6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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primeralph
  • primeralph
draw it.
anonymous
  • anonymous
\[\sqrt{2x-3}\] +5 =6 like this
hartnn
  • hartnn
you can subtract 5 fom both sides, first

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anonymous
  • anonymous
There's no need to draw it though
anonymous
  • anonymous
but its not underneath its next to it
hartnn
  • hartnn
then squaring both sides will make it much simpler then
anonymous
  • anonymous
im so confused
hartnn
  • hartnn
isolate the square root sign by subtracting 5 from both sides...can u?
anonymous
  • anonymous
yea i did that and got 1
hartnn
  • hartnn
correct...now square both sides..
anonymous
  • anonymous
ok and i got 4x²-20x+25
hartnn
  • hartnn
actually, squaring and square root gets cancelled \((\sqrt{A})^2=A\) so, \((\sqrt{2x-3})^2=2x-3\) only got this ?
anonymous
  • anonymous
I will show you how it's done just now that is if you will like how I will do it but even if you don't like my way I will do it my way anyway : \[\sqrt{2x-3}+5=6 \rightarrow \sqrt{2x-3}=6-5 \rightarrow \sqrt{2x-3}=1 \] And now you can square both sides of the equation as follows \[\left( \sqrt{2x-3} \right)^2 = 1^2 \] \[2x-3=1\] \[2x=4 \rightarrow x=2\] but you need to go back and check if the solution makes sense or not hey by substituting your result into the original equation \[\sqrt{2(2)-3} +5=6\] \[\sqrt{4-3}+5=6 \rightarrow \sqrt{1}+5=6 \rightarrow 1+5=6 \] and you can see that hey the left hand side is equal to the right hand side which means that the solution makes sense \[6=6 \rightarrow RHS=LHS\] as expected
anonymous
  • anonymous
kinda?
hartnn
  • hartnn
so its just 2x-3 =1 aon't this easy to solve ?
hartnn
  • hartnn
*ain't
anonymous
  • anonymous
yea i its x=2
hartnn
  • hartnn
correct :)
anonymous
  • anonymous
Does the answer make sense to you though ? Indiandabest ???
anonymous
  • anonymous
i mean kinda i kinda know what to do from now on
anonymous
  • anonymous
Dont I deserve a medal for this at least :)
anonymous
  • anonymous
lol yea
anonymous
  • anonymous
Hahaha thanks

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