anonymous
  • anonymous
Simplify. (2²)‾³
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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ganeshie8
  • ganeshie8
use this :- \(\large a^{-m} = \frac{1}{a^m}\)
anonymous
  • anonymous
lol i dont understand
ganeshie8
  • ganeshie8
okay il show you :) \((2^2)^{-3}\)

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ganeshie8
  • ganeshie8
thats how the given expression is ?
anonymous
  • anonymous
yes
ganeshie8
  • ganeshie8
\(\large (2^2)^{-3}\) first, we get rid of the negative exponent : \(\large \frac{1}{(2^2)^{3}}\)
ganeshie8
  • ganeshie8
\(\large \frac{1}{(4)^{3}}\)
ganeshie8
  • ganeshie8
\(\large \frac{1}{64}\)
ganeshie8
  • ganeshie8
does that makes some sense
anonymous
  • anonymous
Yess but is it neg. or posititve?
ganeshie8
  • ganeshie8
positive oly
ganeshie8
  • ganeshie8
a negative exponent becomes positive when u put it over 1
anonymous
  • anonymous
Ohhhhhh ok thank you soo much
ganeshie8
  • ganeshie8
np :)

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