anonymous
  • anonymous
Solve using the Quadratic Formula. 4x² + 7x + 1 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Please help!! this test is determing if i pass or not
.Sam.
  • .Sam.
\[4x^2 + 7x + 1 = 0\] Written in \[ax^2+bx+c=0\] The quadratic formula is \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] substitute in the values a is 4 b is 7 c is 1
anonymous
  • anonymous
A moment.

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anonymous
  • anonymous
Im still confused!
whpalmer4
  • whpalmer4
What exactly is your point of confusion? Do you not understand how to evaluate the formula, or how it is derived, or ???
Luigi0210
  • Luigi0210
laziness
anonymous
  • anonymous
am i sopose to plug in those values and no im not lazy when i ask question i need help not to answer them for me
anonymous
  • anonymous
Substitute the respective formulas in the equation,it's the simplest.
whpalmer4
  • whpalmer4
.Sam. gave you the formula, and told you to substitute the numbers for each letter (even identifying the values of each letter).
whpalmer4
  • whpalmer4
Your equation is \(4x^2+7x+1=0\) so \(a = 4, b = 7, c = 1\) and the formula is \[x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\] Wherever you see \(a\) substitute 4; \(b\) substitute 7; \(c\) substitute 1
anonymous
  • anonymous
ok and i got -7+ or - \[\sqrt{33}\] over 8
whpalmer4
  • whpalmer4
Very good...
anonymous
  • anonymous
thank you..see im not lazy i just need some help i didnt ask for the answer i asked you to help me
anonymous
  • anonymous
x = 1/8 (-7-sqrt(33))
whpalmer4
  • whpalmer4
I didn't accuse you of laziness, I just asked what was confusing you... @Odero there are two solutions because the polynomial has an x^2 term. the other solution is x = 1/8(-7+sqrt(33))
anonymous
  • anonymous
Ooops,thanks...

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