anonymous
  • anonymous
Check my work please... \[\frac{ -10a ^{-4}b ^{-1} }{ 5a ^{-2}b ^{8} }\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
-10 / 5 = -2 \[a ^{\left( -4 - (-2) \right)} = a ^{-2}\] \[b ^{\left( -1 - 8 \right)} = b ^{-9}\]
anonymous
  • anonymous
Now how do I get the exponents to be positive in the final answer... here is the original question: Simplify the expression: \[\frac{ 10a ^{-4}b ^{-1} }{ 5a ^{-2}b ^{8} }\] Write your answer without negative exponents.
anonymous
  • anonymous
@anyone

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phi
  • phi
\[ -2 a^{-2}b^{-9} \] to change the sign of the exponent, "flip" the base... if up top, put it in the bottom or vice versa
phi
  • phi
so you get -2 over the other stuff
anonymous
  • anonymous
So \[\frac{ -2 }{ a ^{2}b ^{9}}\]
anonymous
  • anonymous
???
phi
  • phi
yes, that is right.
anonymous
  • anonymous
Awsome, thanks for your help!

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