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(2x − 6)(3x2 − 3x − 6). you sure thts rite?
@unheard did you try?
6x3 + 24x2 − 6x + 36
No, I didn't try, because I forgot the method for this one.
@bzbnme Please explain how you got this,
ok...actual i screwed it up... the first term is the same in all cases....the last term must be positive so rule out the second and fourth answers...so the only difference in the first and third one is the second and third terms... x^2 terms are all negative so the real answer should be 6x3 − 24x2 + 6x + 36... sorry for the earlier error!
or just work it out like this \[2x(3x^2-3x-6)-6(3x^2-3x-6)\]
you have to do two things first.|dw:1370365425708:dw| what do you get? :)
@unheard do you understand?
Working it out right now
Take your time
very good:) now simplify it further. Please combine the like terms
There is a small mistake, \[(2x − 6)(3x^2 − 3x − 6)\] \[2x(3x^2-3x-6)-6(3x^2-3x-6)\] \[6x^3-6x^2-12x- (18x^2-18x-36)\] \[6x^3-6x^2-12x-18x^2+18x+36\]
That confused me a bit.
What you just put..
Any step in particular ?
All of it...
Ok, I'll explain again
Dumb it down for me, haha
We have \[(2x − 6)(3x^2 − 3x − 6)\] 2x is multiplied to the second bracket and -6 is multiplied to the second bracket \[2x\times (3x^2-3x-6) -6\times(3x^2-3x-6)\] Do you get this part?
Yes. I did that.
Yea, now we do the multiplication \[6x^3-6x^2-12x- 6(3x^2-3x-6)\] Now I'll multiply 6 to the bracketed term and keep minus sign outside \[6x^3-6x^2-12x-(18x^2-18x-36)\] Do you get this?
Yeah, didn't I just do that...
Yes, there was a minus error, when you multiplied -6
Ok, so what did I need to fix? Sorry.. I'm really scatterbrained right now, trying to do two algebra problems at once.
Check this, http://www.sketchtoy.com/36455506
last step, I did the changes
check this http://www.sketchtoy.com/36455851
You understood? there was a tiny mistake
Yeah, got it, thanks