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The graph of which equation is shown below?

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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y = −x^2 + 2x − 3 y = −x^2 − 2x − 3 y = x^2 + 2x − 3 y = x^2 − 2x − 3

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Other answers:

the first answer choice The roots of the equation are found anywhere the equation y=x^2-2x-3 is equal to zero, like the question states. To do this you must first factor the equation. x^2 is easy enough, it splits into two x's, so you start with: (x )(x ) Now you have to find the combinations that multiply to give -3 and who's sum is -3. We can use +1 and -3, giving us: (x+1)(x-3) = 0 We can make the equation equal to zero by making either of two brackets equal to zero, so the equation's roots lie at x=-1 and x=3.

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