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Haleyy_Bugg Group TitleBest ResponseYou've already chosen the best response.0
y = −x^2 + 2x − 3 y = −x^2 − 2x − 3 y = x^2 + 2x − 3 y = x^2 − 2x − 3
 one year ago

Haleyy_Bugg Group TitleBest ResponseYou've already chosen the best response.0
@Notamathgenius
 one year ago

Notamathgenius Group TitleBest ResponseYou've already chosen the best response.0
the first answer choice The roots of the equation are found anywhere the equation y=x^22x3 is equal to zero, like the question states. To do this you must first factor the equation. x^2 is easy enough, it splits into two x's, so you start with: (x )(x ) Now you have to find the combinations that multiply to give 3 and who's sum is 3. We can use +1 and 3, giving us: (x+1)(x3) = 0 We can make the equation equal to zero by making either of two brackets equal to zero, so the equation's roots lie at x=1 and x=3.
 one year ago
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