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Haleyy_Bugg

  • 2 years ago

The graph of which equation is shown below?

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  1. Haleyy_Bugg
    • 2 years ago
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  2. Haleyy_Bugg
    • 2 years ago
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    y = −x^2 + 2x − 3 y = −x^2 − 2x − 3 y = x^2 + 2x − 3 y = x^2 − 2x − 3

  3. Haleyy_Bugg
    • 2 years ago
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    @Notamathgenius

  4. Notamathgenius
    • 2 years ago
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    the first answer choice The roots of the equation are found anywhere the equation y=x^2-2x-3 is equal to zero, like the question states. To do this you must first factor the equation. x^2 is easy enough, it splits into two x's, so you start with: (x )(x ) Now you have to find the combinations that multiply to give -3 and who's sum is -3. We can use +1 and -3, giving us: (x+1)(x-3) = 0 We can make the equation equal to zero by making either of two brackets equal to zero, so the equation's roots lie at x=-1 and x=3.

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