## carlenstar281 2 years ago math hw question

1. Luigi0210

Difference of two perfect squares.. (x-9)(x+9)

2. Luigi0210

(s-9)(s+9)

3. Luigi0210

only if I get a medal.. haha jk sure :P

4. carlenstar281

sorry lol i thought i gave you one

5. Luigi0210

Well first we have to get the c term by using (b/2)^2 $(-\frac{ 6 }{ 2 })^2=9$ So now add that to both sides: $(x^2-6x+9)=-8+9$ Simplify: $(x-3)^2=1$

6. Luigi0210

Now take the square root of both sides: $\sqrt{(x-3)^2}=\pm \sqrt{1}$ Since the square root of 1 is 1 we leave it: $x-3= \pm1$ Now add 3: $x-3+3=\pm1+3$ $x=\pm1+3$ Separate and do then separately: $x=1+3=4$ $x-1+3=2$ And there you go :)

7. carlenstar281

oh wow you make it easy thanks for showing me how you do it not i will be able to do the rest on my own thanks so much :)

8. Luigi0210

No problem, happy to help :D