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carlenstar281

math hw question

  • 10 months ago
  • 10 months ago

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  1. Luigi0210
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    Difference of two perfect squares.. (x-9)(x+9)

    • 10 months ago
  2. Luigi0210
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    (s-9)(s+9)

    • 10 months ago
  3. Luigi0210
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    only if I get a medal.. haha jk sure :P

    • 10 months ago
  4. carlenstar281
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    sorry lol i thought i gave you one

    • 10 months ago
  5. Luigi0210
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    Well first we have to get the c term by using (b/2)^2 \[(-\frac{ 6 }{ 2 })^2=9\] So now add that to both sides: \[(x^2-6x+9)=-8+9\] Simplify: \[(x-3)^2=1\]

    • 10 months ago
  6. Luigi0210
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    Now take the square root of both sides: \[\sqrt{(x-3)^2}=\pm \sqrt{1}\] Since the square root of 1 is 1 we leave it: \[x-3= \pm1\] Now add 3: \[x-3+3=\pm1+3\] \[x=\pm1+3\] Separate and do then separately: \[x=1+3=4\] \[x-1+3=2\] And there you go :)

    • 10 months ago
  7. carlenstar281
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    oh wow you make it easy thanks for showing me how you do it not i will be able to do the rest on my own thanks so much :)

    • 10 months ago
  8. Luigi0210
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    No problem, happy to help :D

    • 10 months ago
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