anonymous
  • anonymous
Can you show me why logn^2 = 2log2n?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\log_{}n ^{2} = 2\log_{2}n \]
dumbcow
  • dumbcow
its an identity \[\log (n^{a}) = a \log(n)\] you could also prove it using product identity \[\log(n^{2}) = \log(n*n) = \log(n) +\log(n) = 2\log(n)\]
anonymous
  • anonymous
ah ok, but why does the base change from base 10 to base 2?

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anonymous
  • anonymous
or I think maybe the 1st one is actually base 2 as well...
dumbcow
  • dumbcow
umm yeah identities only work with like bases...
amistre64
  • amistre64
log(n^2) log(n*n) log(n) + log(n) 2 log(n)
amistre64
  • amistre64
thrms are not accepted on faith ... they are proven or rejected
anonymous
  • anonymous
ok thanks everyone
anonymous
  • anonymous
thanks too amistre
amistre64
  • amistre64
yep :)

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